Opening brackets gives;
4-8v=-8v+4
Putting like terms together;
4-4=-8v+8v
0=0
There is no solution thus.
Answer:You divide 5 by 33, which is 0.151515 (with the 15 repeating)
Step-by-step explanation:
Answer:
1. 40%
2. The theoretical probability is 3% greater than the experimental probability.
Step-by-step explanation:
We are informed that a number cube is rolled 20 times and the number 4 is rolled 8 times. The experimental probability of rolling a 4 is;
(the number of times a 4 was rolled)/(total number of rolls)
8/20 = 0.4
0.4*100 = 40%
The experimental probability of obtaining at least one tails, one or more tails, is represented in mathematical notation as;
P(HT or TH or TT)
The above events are mutually exclusive, thus;
P(HT or TH or TT) = P(HT) + P(TH) + P( TT)
= (22+34+16)/(28+22+34+16)
= 0.72 = 72%
On the other hand, the theoretical probability of obtaining at least one tails,
P(HT or TH or TT) = 3/4
= 75%
This is because there is at least one tail in 3 out of 4 possible outcomes.
Therefore, it is true to say that the theoretical probability is 3% greater than the experimental probability.
1 cm is the base of the triangle
25% is being taken off the original price, p, of each patio chairs.
That means the price of each patio chair is the full price, p, minus <span>25% of the original price.
1) To find 25% of the original price, multiply p (original price) by the decimal form of 25%, or 0.25. That means 25% off original price = 0.25p.
2) Now subtract 0.25p from the original price of the chairs to find the price of each (1) chair. p - 0.25p
Shylah is buying 4 chairs at that discounted price. That means you need to multiply the discounted price, </span> p - 0.25p, by 4. Shylah is paying 4(p-0.25p) total for the 4 chairs, which is answer choice B.
Since you can choose more than one choice, you can simplify 4(p-0.25p) by subtracting what is in the parathesis, then multiplying, following the order of operations:
4(p-0.25p)
= 4(0.75p)
= 3p
That is answer choice A.
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Answer: Choices A and B, <span>3p and 4(p−0.25p).</span>
