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Brilliant_brown [7]
2 years ago
6

How do I solve the following equation

Mathematics
2 answers:
nalin [4]2 years ago
7 0

Answer:

z = 72

Step-by-step explanation:

-1/4z + 12 = -6

× 4

-z + 48 = - 24

-z = - 72

z = 72

Tatiana [17]2 years ago
4 0
-6-12=-1/4z
-18=-1/4z
Z=-18/-./25
Z=72

Plz check it
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Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5x minus 8 when x is less than 0 a
vlabodo [156]
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:

We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8

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If we would continue the limit (extend the zeros to infinity), we would get exactly
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Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)

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3 years ago
Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ
tensa zangetsu [6.8K]

Answer:    RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= \frac{18+x}{RQ}

⇒ RQ=  \frac{18+x}{tan 75^{\circ}}

Now, In triangle MRQ,

tan 60°= \frac{18+x}{RQ}

⇒ RQ=  \frac{x}{tan 60^{\circ}}

On equating both values of RQ,

\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=2.15470053838

⇒18=2.15470053838x-x

⇒x=15.5884572681≈15.60

Thus RQ=8.99999999999≈8.99


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