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Molodets [167]
2 years ago
13

Solve this inequality algebracially. |3-x|>10

Mathematics
2 answers:
xeze [42]2 years ago
8 0

Answer:

x < -7 or x > 13

Step-by-step explanation:

3 - x < -10 or 3 - x > 10

-x < -13      or    -x > 7

x > 13         or    x < -7

Answer: x < -7 or x > 13

Nady [450]2 years ago
5 0

Answer:

x < -7 or x > 13

Step-by-step explanation:

<em>Solving Absolute Value</em>

  • <u></u>|-x+3| > 10
  • We know that either -x + 3 > 10 or -x + 3 < -10

<u>Possibility 1:</u>

Step 1: Subtract 3 from both sides.

  • -x + 3-3>10-3
  • -x > 7

Step 2: Divide both sides by -1.

  • \frac{-x}{-1} > \frac{7}{-1}
  • x < -7

<u>Possibility 2:</u>

Step 1: Subtract 3 from both sides.

  • -x + 3 - 3 < -10 - 3
  • -x < -13

Step 2: Divide both sides by -1.

  • \frac{-x}{-1} < \frac{-13}{-1}
  • x > 13

Therefore, the answer is x < -7 or x > 13.

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Answer:

Step-by-step explanation:

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2 years ago
Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

                                               =3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z

Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

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3 years ago
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Step-by-step explanation:

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2 years ago
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