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2 years ago

How to select multiple layers in photoshop

1 answer:

3 0

Answer: Click a layer in the Layers panel. To select multiple contiguous layers, click the first layer and then Shift-click the last layer. To select multiple noncontiguous layers, Ctrl-click (Windows) or Command-click (Mac OS) them in the Layers panel.

Explanation:

You might be interested in

HELLLP

mojhsa [17]

Explanation:

The output of this program is 5 7, because the first time bruce is printed, his value is 5, and the second time, his value is 7. The comma at the end of the first print statement suppresses the newline after the output, which is why both outputs appear on the same line.

Here is what multiple assignment looks like in a state diagram:

With multiple assignment it is especially important to distinguish between an assignment operation and a statement of equality. Because Python uses the equal sign (=) for assignment, it is tempting to interpret a statement like a = b as a statement of equality. It is not!

First, equality is symmetric and assignment is not. For example, in mathematics, if a = 7 then 7 = a. But in Python, the statement a = 7 is legal and 7 = a is not.

Furthermore, in mathematics, a statement of equality is always true. If a = b now, then a will always equal b. In Python, an assignment statement can make two variables equal, but they don’t have to stay that way:

a = 5

4 0

2 years ago

Read 2 more answers

Microsoft word's spelling checker will offer suggestions on misspelled words.<br> True)<br> False)

Rasek [7]

This is true. I hope I was helpful!

7 0

3 years ago

Read 2 more answers

Which of these is a historic real-world simulation game?

harkovskaia [24]

Answer:

B. Archery

Explanation:

the art, practice, or skill of shooting with bow and arrow

7 0

2 years ago

Write a Python program that takes a file name as input and generates the following output: File size in bytes and KBs Time the f

Airida [17]

Answer:

See explaination

Explanation:

import os

import time

from stat import *

file = input("Enter file name: ")

details = os.stat(file)#stores statistics about a file in a directory

print("File size: ", details[ST_SIZE])#retreiving size

print("File last accessed time: ", time.asctime(time.localtime(details[ST_ATIME])))#access time

print("File last modified time: ", time.asctime(time.localtime(details[ST_MTIME])))#modified time

print("File creation time: ", time.asctime(time.localtime(details[ST_CTIME])))#creation time

print("First character: ", file[0])

print("Middle character: ", file[len(file) // 2])

print("Last character: ", file[len(file) - 1])

num_words = 0

num_lines = 0

f=open(file, "r")

lines = f.readlines()

for line in lines:

num_lines = num_lines + 1

num_words = num_words + len(line.split())#add no. of words in that line

print("Number of lines: ", num_lines)

print("Number of words: ", num_words)

8 0

2 years ago

Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static

yKpoI14uk [10]

Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

// main method

public static void main(String[] args) {

// create a list of Comparable type

List<Comparable> list = new ArrayList<>();

// add elements

list.add(1);

list.add(2);

list.add(3);

list.add(4);

list.add(5);

list.add(6);

list.add(7);

// print list

System.out.println("\nList : "+list);

// test search method

Comparable a = 7;

System.out.println("\nSearch for 7 : "+search(list,a));

Comparable b = 3;

System.out.println("\nSearch for 3 : "+search(list,b));

Comparable c = 9;

System.out.println("\nSearch for 9 : "+search(list,c));

Comparable d = 1;

System.out.println("\nSearch for 1 : "+search(list,d));

Comparable e = 12;

System.out.println("\nSearch for 12 : "+search(list,e));

Comparable f = 0;

System.out.println("\nSearch for 0 : "+search(list,f));

}

// static method named search takes arguments Comparable list and Comparable parameter

public static boolean search(List<Comparable> list, Comparable par) {

// if list is empty or parameter is null the throw IllegalArgumentException

if(list.isEmpty() || par == null ) {

throw new IllegalArgumentException();

}

// binary search

// declare variables

int start=0;

int end =list.size()-1;

// using while loop

while(start<=end) {

// mid element

int mid =(start+end)/2;

// if par equal to mid element then return

if(list.get(mid).equals(par) )

{

return true ;

}

// if mid is less than parameter

else if (list.get(mid).compareTo(par) < 0 ) {

start=mid+1;

}

// if mid is greater than parameter

else {

end=mid-1;

}

// if not found then retuen false

return false;

}

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

// main method

public static void main(String[] args) {

// create a list of Comparable type

List<Comparable> list = new ArrayList<>();

// add elements

list.add(1);

list.add(2);

list.add(3);

list.add(4);

list.add(5);

list.add(6);

list.add(7);

// print list

System.out.println("\nList : "+list);

// test search method

Comparable a = 7;

System.out.println("\nSearch for 7 : "+search(list,a));

Comparable b = 3;

System.out.println("\nSearch for 3 : "+search(list,b));

Comparable c = 9;

System.out.println("\nSearch for 9 : "+search(list,c));

Comparable d = 1;

System.out.println("\nSearch for 1 : "+search(list,d));

Comparable e = 12;

System.out.println("\nSearch for 12 : "+search(list,e));

Comparable f = 0;

System.out.println("\nSearch for 0 : "+search(list,f));

}

// static method named search takes arguments Comparable list and Comparable parameter

public static boolean search(List<Comparable> list, Comparable par) {

// if list is empty or parameter is null the throw IllegalArgumentException

if(list.isEmpty() || par == null ) {

throw new IllegalArgumentException();

}

// binary search

// declare variables

int start=0;

int end =list.size()-1;

// using while loop

while(start<=end) {

// mid element

int mid =(start+end)/2;

// if par equal to mid element then return

if(list.get(mid).equals(par) )

{

return true ;

}

// if mid is less than parameter

else if (list.get(mid).compareTo(par) < 0 ) {

start=mid+1;

}

// if mid is greater than parameter

else {

end=mid-1;

}

// if not found then retuen false

return false;

}

7 0

2 years ago