Answer:
Step-by-step explanation:
the volume of a cylinder is given by:
and the volume of a cone is given by:
since both have the same height and radius, we can solve each equation for 
(because this quantity is the same in both figures) and then match the expressions we find:
from the cylinder's volume formula:
and from the cone's volume formula:
matching the two previous expressions:
we solve for the volume of a cone 
:
substituting the value of the cylinder's volume 
<u>Answer-</u>
<em>For </em><em>side length of 3.56 cm</em><em> and </em><em>height of 7.10 cm</em><em> the cost will be minimum.</em>
<u>Solution-</u>
Let us assume that,
x represents the length of the sides of the square base,
y represent the height.
Given the volume of the box is 90 cm³, so
As the top and bottom cost $0.60 per cm² and the sides cost $0.30 per cm². Total cost C will be,
Then,
As C'' has all positive terms so, for every positive value of x (as length can't be negative), C'' is positive.
So, for minima C' = 0
Then,
Therefore, for side length of 3.56 cm and height of 7.10 cm the cost will be minimum.
Answer:
5.1
Step-by-step explanation:
Compounded Annually:
A=P(1+r)^t
A=P(1+r)
t
A=27200\hspace{35px}P=20000\hspace{35px}r=0.062
A=27200P=20000r=0.062
Given values
27200=
27200=
\,\,20000(1+0.062)^{t}
20000(1+0.062)
t
Plug in values
27200=
27200=
\,\,20000(1.062)^{t}
20000(1.062)
t
Add
\frac{27200}{20000}=
20000
27200
=
\,\,\frac{20000(1.062)^{t}}{20000}
20000
20000(1.062)
t
Divide by 20000
1.36=
1.36=
\,\,1.062^t
1.062
t
\log\left(1.36\right)=
log(1.36)=
\,\,\log\left(1.062^t\right)
log(1.062
t
)
Take the log of both sides
\log\left(1.36\right)=
log(1.36)=
\,\,t\log\left(1.062\right)
tlog(1.062)
Bring exponent to the front
\frac{\log\left(1.36\right)}{\log\left(1.062\right)}=
log(1.062)
log(1.36)
=
\,\,\frac{t\log\left(1.062\right)}{\log\left(1.062\right)}
log(1.062)
tlog(1.062)
Divide both sides by log(1.062)
5.1116317=
5.1116317=
\,\,t
t
Use calculator
t\approx
t≈
\,\,5.1
5.1
So he goes from side 2 to side 4 there is his cut have a nice day sir/maam
