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4 years ago

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For Jane's Uber business, She charges 5$ intial fee and $0.10 a mile. Joe's Uberbusiness charges $4 initial fee and $.0.20 a mil

e. Write a function for Jane's Uber business Write a function for Joe's Uber business

1 answer:

marusya05 [52]4 years ago

7 0

jane- y=0.10x+5

joe- y=0.20x+4

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Write g(x) = 4x2 + 88x in vertex form. The function written in vertex form is g(x) = ___ (x +11)2 +____.

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$The\ vertex\ form:\\\\f(x)=a(x-h)^2+k$

$\text{Use}\ (a+b)^2=a^2+2ab+b^2\qquad(*)$

$g(x)=4x^2+88x=4(x^2+22x)=4(x^2+2\cdot x\cdot11)\\\\=4(\underbrace{x^2+2\cdot x\cdot11+11^2}_{(*)}-11^2)=4[(x+11)^2-121]=4(x+11)^2+(4)(-121)=4(x+11)^2-484$

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3 years ago

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The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.

<h3>What are the steps of this construction?</h3>

1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.

2. Without altering it, with the aid of the compass, do draw an art above and also below the said line segment from one of the segment endpoints.

3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.

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2 years ago

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Answer:

Part 1) The surface area of the triangular prism is $SA=660\ cm^{2}$

Part 2) The surface area of the trapezoidal prism is $SA=2,864\ cm^{2}$

Step-by-step explanation:

Part 1) Find the surface area of the triangular prism

we know that

The surface area is equal to

$SA=2B+PL$

where

B is the area of the triangular base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

<u>Find the area of the triangular base B</u>

$B=\frac{1}{2}(10)(12)=60\ cm^{2}$

<u>Find the perimeter of the base P</u>

$P=10+13+13=36\ cm$

$L=15\ cm$

substitute the values

$SA=2(60)+(36)(15)=660\ cm^{2}$

Part 2) Find the surface area of the trapezoidal prism

we know that

The surface area is equal to

$SA=2B+PL$

where

B is the area of the trapezoid base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

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$B=\frac{1}{2}(28+15)(8)=172\ cm^{2}$

<u>Find the perimeter of the base P</u>

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$L=40\ cm$

substitute the values

$SA=2(172)+(63)(40)=2,864\ cm^{2}$

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