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Troyanec [42]
3 years ago
12

If the nth term of a number sequence is 5n– 2n, find the first 3 terms and the 10th term.

Mathematics
1 answer:
rewona [7]3 years ago
6 0

To answer this question, you need to subtitute a number for each n. First find the first and then push off of there.

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If exactly 194 people sign up for a charter flight, Leisure World Travel Agency charges $312/person. However, if more than 194 p
maw [93]

Title:

<h2>The revenue will be maximum for 253 passengers.</h2>

Step-by-step explanation:

Let, the number of passenger is x, which is more than 194.

In this case, the travel agency will charge [312 - (x - 194)] per passenger.

The total revenue will be x[312 - (x - 194)] = 506x - x^{2}.

As x is the variable here, we can represent the revenue function by R(x). Hence, R(x) = 506x - x^{2}.

The revenue will be maximum when \frac{d (506x - x^{2} )}{dx} = 0\\2x = 506\\x = 253.

6 0
3 years ago
F(x) = 1/3x -2; reflection in the x-axis
san4es73 [151]
Would it be -1/3x -2?
4 0
3 years ago
How do u write 5(2x - 1) in a distributive property
Nookie1986 [14]

Answer:

5(2x-1) = 5(2x) - 5(1)

Step-by-step explanation:

The distributive property states that multiplying a sum or difference of two terms by a number is equal to multiplying the same number with each term of the sum or difference separately and then adding the products.

It can be written as:

a(b+c) = ab + ac

or

a(b-c) = ab - ac

So, for the given question,

=>5(2x-1) = 5(2x) - 5(1)

5 0
3 years ago
Frank monitors the cost of gasoline for his budget. The table below shows Frank's gasoline purchases for the month of June. What
Norma-Jean [14]

Answer: 2.49 gallons

Step-by-step explanation:

$32.37 divided by 13 is 2.49 :)

4 0
3 years ago
A cylinder shaped can needs to be constructed to hold 600 cubic centimeters of soup. The material for the sides of the can costs
PSYCHO15rus [73]

Answer:

the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

Step-by-step explanation:

since the volume of a cylinder is

V= π*R²*L → L =V/ (π*R²)

the cost function is

Cost = cost of side material * side area  + cost of top and bottom material * top and bottom area

C = a* 2*π*R*L + b* 2*π*R²

replacing the value of L

C = a* 2*π*R* V/ (π*R²) + b* 2*π*R²  = a* 2*V/R + b* 2*π*R²

then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then

dC/dR = -2*a*V/R² + 4*π*b*R = 0

4*π*b*R = 2*a*V/R²

R³ = a*V/(2*π*b)

R=  ∛( a*V/(2*π*b))

replacing values

R=  ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm

then

L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm

therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

5 0
4 years ago
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