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Troyanec [42]
3 years ago
12

If the nth term of a number sequence is 5n– 2n, find the first 3 terms and the 10th term.

Mathematics
1 answer:
rewona [7]3 years ago
6 0

To answer this question, you need to subtitute a number for each n. First find the first and then push off of there.

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Roberto has $200 in spending money. He wants to buy some video games that cost $25.50 each. Write and solve an inequality to fin
Veseljchak [2.6K]

Answer:

f(x) = 25.50x      Roberto can buy 7 video games

Step-by-step explanation:

Each game is $25.50 which in math means it has an "x"

So if x=1 then 25.50x says that 1 video game is $25.50

Set up the equation:

200 = 25.50x (divide both sides by 25.50 to isolate the x)

200/25.50 = 7.84

x = 7.84

You can't have 0.84 of a video game, so Roberto can only buy 7 of them.

3 0
3 years ago
Read 2 more answers
Solve 5n – 7p + 3n = 25p for n.
saul85 [17]

5n – 7p + 3n = 25p

Combine like terms

8n - 7p = 25p

Add (7p) to both sides

8n - 7p + 7p = 25p + 7p

Simplifying

8n = 32p

Divide both sides by 8

8n / 8 = 32p / 8

Simplifying

n = 4p

7 0
3 years ago
Read 2 more answers
Convert 2.8 radians to degree measure. Round your answer to the nearest hundredth.​
Sergeeva-Olga [200]

Answer:

16.04°

Step-by-step explanation:

2.8 \: rad = x \: degrees \\

1rad × 180/π = 57.296°

x = 2.8 \times  \frac{180}{\pi}  = 16.0428 \\ x = 16.04

8 0
3 years ago
The wall is to be 5ft by 7 ft. A brick is 4 inches by 12 inches. How many bricks are needed
Tatiana [17]

you need 83 bricks i believe

3 0
3 years ago
Suppose an airline policy states that all baggage must be box shaped with a sum of length, width, and height not exceeding 174 i
Leya [2.2K]

Answer:

The square-based box with the greatest volume under the condition that the sum of length, width, and heigth does not exceed 174 in is a cube with each edge of 58 in and a volume of 195112 in^{3}

Step-by-step explanation:

For this problem we have two constraints, that are as follows:

1) Sum of length, width, and heigth not exceeding 174 in

2) Lenght and width have the same measure (square-based box)

We know that volume is equal to the product of all three edges, and with the two conditions into account we have the next function:

V=(w^{2})(174-2w)\\V=174w^{2}-2w^{3}

The interval of interest of the objective function is [0, 87]

This problem requieres that we maximize the function that defines the volume. We start calculating the derivative of the function, wich is:

V'=348w-6w^{2} \\V'=(348-6w)(w)

We need to remember that the derivative of a function represents the slope of said function at a given point. The maximum value of the function will have a slope equal to zero.

So we find the value in wich the derivative equals zero:

0=(348-6w)(w)\\w_1=0\\w_2=348/6=58

The first value (w=0) will leave us with a 'height-only box', so the answer must be w=58 in

The value is between the interval of interest.

And, once we solve for the constraints, we have that:

Lenght = Width = Heigth = 58 in

Volume = 195112 in^{2}

8 0
3 years ago
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