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Whitepunk [10]
2 years ago
11

PLEASE HELP AS SOON AS POSSIBLE! Please look at the attached image, I greatly appreciate it!

Mathematics
1 answer:
lukranit [14]2 years ago
6 0

Answer:

x^2 = 10^2 - 9^2

x^2 = 100 -81 = 19

x = 4.3588989435

The triangle sides are 10, 9 and 4.3588989435

Step-by-step explanation:

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Out of 5,400 raffle tickets sold at the carnival, 180 are winners. At this same rate, how many winning raffles tickets can be ex
Triss [41]
Out of 5,400 raffle tickets sold at the carnival, 180 are winners. At this same rate, how many winning raffles tickets can be expected if 8,100 raffle tickets are sold? 247
5 0
3 years ago
Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has. How m
exis [7]

Answer:

a) Write a let statement below to define your variable(s):

Let the number of fishes Ms. Montesinos has be represented by = f

b) Set up an equation using the variable you defined in (a):

The equation is :

3f - 2 = 13

c) Solve your equation & Check. How many fish does Ms. Montesinos have?

Ms. Montesinos has 5 fishes

Step-by-step explanation:

Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has. How many fish does Ms. Montesinos have in her tank?

a) Write a let statement below to define your variable(s):

Let the number of fishes Ms. Montesinos has be represented by = f

b) Set up an equation using the variable you defined in (a):

We are told in the question:

Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has.

Therefore,

3× f - 2 = 11 + 2

The equation is :

3f - 2 = 13

c) Solve your equation & Check. How many fish does Ms. Montesinos have?

Solving the above equation:

3f - 2 = 13

3f = 13 + 2

3f = 15

Divide both sides by 3

3f/3 = 15/3

f = 5

Hence, Ms. Montesinos has 5 fishes

4 0
3 years ago
HELPPP ASAPPP DUE SOONN
Andru [333]

The friction force exerted on the 2400kg car is 9408 Newtons

<h3>What force will be exerted on the 2400kg car?</h3>

First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:

F = k*M

Where F is the force, M is the mass and k is the constant of proportionality.

We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:

6272N = k*1600kg

Solving for k we get:

k  = (6272N)/(1600 kg) = 3.92 N/kg

Then the proportional relationship is:

F = (3.92 N/kg)*M

So if M = 2400kg, we have:

F = (3.92 N/kg)*2400kg = 9408 N

So the friction force exerted on the 2400kg car is 9408 Newtons

If you want to learn more about proportional realtions:

brainly.com/question/12242745

#SPJ1

8 0
2 years ago
If △PQR ~ △STU, find ST
cupoosta [38]

Answer:

Do you have any pictures??

6 0
3 years ago
Apply the distributive property to factor out the greatest common factor of all three terms 14x+21y+7z=
Elenna [48]

Answer:

7(2x+3y+z)

Step-by-step explanation:

14x+21y+7z

Factor out 7

7*2x+ 7*3y+7*z

7(2x+3y+z)

8 0
3 years ago
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