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mote1985 [20]
2 years ago
15

What part of 8 is 64

Mathematics
2 answers:
aev [14]2 years ago
3 0

Answer:

I believe the answer would be 1/8 of 64

Step-by-step explanation:

I think it means what fraction of 64 is 8, so in that case, 8 would be 1/8 of 64.

Pavel [41]2 years ago
3 0
Assuming u mean what fraction of 64 is 8 the answer will indeed be 1/8, or 12.5%

This is correct because 8/8 equals 1 whole and 8x8 is 64
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Which is the graph of f(x) = (x – 1)(x + 4)?
Arada [10]

Answer:

The fourth graph (last graph)

Step-by-step explanation:

Remember that the zeros of a function are the x-intercepts of the graph. To find the zeros we just need to set the function equal to zero and solve for x:

f(x)=(x-1)(x+4)

(x-1)(x+4)=0

x-1=0,x+4=0

x=1,x=-4

Now we know that the graph or our function intersects the x-axis at x = 1 and x = -4.

Since both x values inside the parenthesis are positive, our parabola is opening upwards.

The only graph opening upwards whose x-intercepts are x = 1 and x = -4 is the fourth one.

We can conclude that the graph of f(x)=(x-1)(x+4) is the fourth one.

5 0
3 years ago
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Find the are area of the square ABCD​
san4es73 [151]

Answer:

196 m2

Step-by-step explanation:

4 0
3 years ago
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Question 27 of 28<br> 1 Point<br> What is the slope of the line shown below?<br> (3,-2)<br> (2,-4)
Gwar [14]

Answer:

The slope is 2

Step-by-step explanation:

To find the slope given two points, we use the formula

m = (y2-y1)/(x2-x1)

   = (-4--2)/(2-3)

   = (-4+2)/(2-3)

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6 0
3 years ago
A certain slot machine has three identical independent wheels, each with 13 symbols as follows: 1 bar, 2 lemons, 2 bells, 2 plum
kari74 [83]

Answer:

Step-by-step explanation:

Given

there are 13 symbols in slot machines i.e. 1 bar , 2 lemons , 2 bells ,2 plums ,3 cherries , 3 oranges

there are Total of 3 machines

Probability of getting bar in machine is \frac{1}{13}

Probability of getting 3 bar on 3 machine=\frac{1}{13} \times\frac{1}{13}\times \frac{1}{13}=\frac{1}{2197}=0.0004

Probability of getting an orange=\frac{3}{13}

Probability of getting 3 oranges  on 3 machine=\frac{3}{13} \times\frac{3}{13}\times \frac{3}{13}=\frac{27}{2197}=0.0122

Probability of getting a Plum=\frac{2}{13}

Probability of getting 3 Plums  on 3 machine=\frac{2}{13} \times\frac{2}{13}\times \frac{2}{13}=\frac{8}{2197}=0.0036

5 0
3 years ago
What is the coefficient of x2y3 in the expansion of (2x + y)5?
Zigmanuir [339]

Option C:

The coefficient of x^{2} y^{3} is 40.

Solution:

Given expression:

(2 x+y)^{5}

Using binomial theorem:

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here a=2 x, b=y

Substitute in the binomial formula, we get

(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}

                                                            $+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}

Let us solve the term one by one.

$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}

$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y

$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

5 0
3 years ago
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