Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:

Step-by-step explanation:
Answer:
-1/2
Step-by-step explanation:
counting down by 2 over one
Hola!
-6 (3x - 5)
[ simplifying. ]
-18x + 30
hope it helps!
Answer:
The length of the garden=14 feet
Step-by-step explanation:
<em>Step 1: Determine the dimensions of the garden</em>
length of the garden=x feet
width of the garden=(x-4) feet
<em>Step 2: Determine the area of the garden</em>
Area of the garden=length×width
where;
area=140
length=x
width=x-4
replacing'
x(x-4)=140
x²-4x-140=0, solve the quadratic equation;
x={-b±√(b²-4ac)}/2a
x={4±√4²-4×1×-140}/2×1
x={4±√(16+560)}/2
x={4±√576}/2
x=(4±24)/2
x=(4+24)/2=14, or (4-24)/2=-10, take x=14
The length=14 feet, width=(14-4)=10 feet
The length of the garden=14 feet