Question

Please please help me please help now please please help and show your steps help NOW PLEASE please help

Answer 1

Answer:

$x=3, y=-1$

Step-by-step explanation:

We know that $lcm(7, 2)=14$, so we need to multiply equation $1$ by $2$.

This gives $2(4x-7y)=2(19)$, which simplifies to $8x-14y=38$.

We know that $lcm(2, 7)=14$, so we need to multiply equation $2$ by $7$.

This gives $7(3x-2y)=7(11)$, which simplifies to $21x-14y=77$.

Aha! Now we have a path to the solution!

We can subtract the first equation from the second to eliminate $y$.

This gives $(21x-14y)-(8x-14y)=(77)-(38)$, which simplifies to $13x=39$.

We can then divide by $3$ to obtain $x=3$!

Then, we plug $x=3$ into the second equation to get $3(3)-2y=11$.

We can subtract $9$ from both sides to get $-2y=2$.

We then divide by $-2$ to obtain $y=-1$.

So, $x=3$ and $y=-1$, and we're done!