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Novosadov [1.4K]
3 years ago
9

Help. i need to know how to do these for quiz tomorrow.

Mathematics
1 answer:
sdas [7]3 years ago
7 0

I'm not sure about all of the questions, but I'll help with what I can.

1. 93 + 96 - (-5) + 92 = 286

93 + 96 = 189

189 - (-5) = 194

194 + 92 = 286

2. 3/4 + 5/6 = 1 7/12

Common denominator: 12

9/12 + 10/12 = 19/12

Simplify: 1 7/12

3. (-9)(3)(-5) = 135

-9 × 3 = -27

-27 × -5 = 135

4. 24/((-4) + 2) × 2 = -6

(-4) + 2 = -2

-2 × 2 = -4

24/-4 = -6

5. z - y + x - IyI (I couldn't find the actual mathematical symbol, so I just used two lowercase L's) use x = 9, y = -6, z = -5

-5 - -6 - l-6l

1 - 6 = -5

z - y + x - IyI = -5

6. -13 + n = -33

-13 + 13 + n = -33 + 13

n = -20

Not sure about 7

8. lv + 7l  = 12

lv + 7 - 7l = 12 - 7

lvl = 5

Not sure about the rest

Hope I was able to help!

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Solving by factoring.
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8 0
3 years ago
Oliver deposits $1,000 in his Interest-bearing bank account. The balance increases by %15 each month
Volgvan

Step-by-step explanation:

Oliver deposits P= $1,000

Then total amount A after n months given that the balance increases by %15 each month can be calculated as

A= 1000(1+15/100)^n

Assuming the increase in amount is compounded monthly.

5 0
3 years ago
Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x square
N76 [4]

The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is \frac{x^2}{10} + \frac{y^2}{15} = 1

<h3>How to determine the equation of the hyperbola?</h3>

The given parameters are:

  • Directrices at x = ±2
  • Foci at (5, 0) and (−5, 0)

The foci of a hyperbola are represented as:

Foci = (k ± c, h)

The center is:

Center = (h,k)

And the directrix is:

Directrix, x = h ± a²/c

By comparison, we have:

k ± c = ±5

h = 0

h ± a²/c = ±2

Substitute h = 0 in h ± a²/c = ±2

0 ± a²/c = ±2

This gives

a²/c = 2

Multiply both sides by c

a² = 2c

k ± c = ±5 means that:

k ± c = 0 ± 5

By comparison, we have:

k = 0 and c = 5

Substitute c = 5 in a² = 2c

a² = 2 * 5

a² = 10

Next, we calculate b using:

b² = c² - a²

This gives

b² = 5² - 10

Evaluate

b² = 15

The hyperbola is represented as:

\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1

So, we have:

\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1

Evaluate

\frac{x^2}{10} + \frac{y^2}{15} = 1

Hence, the equation of the hyperbola is \frac{x^2}{10} + \frac{y^2}{15} = 1

Read more about hyperbola at:

brainly.com/question/3405939

#SPJ1

6 0
2 years ago
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d1i1m1o1n [39]
-77 PEMDAS is the process you would use and you would have to do the associative property with-(3--4)
4 0
4 years ago
Hallar el valor de x en 3(x-2)+4=x-5
kolezko [41]

Answer:

exact form 3/2 decimal  form 1.5 mixed number form 1 1/2

Step-by-step explanation:

8 0
3 years ago
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