Order these from greatest to least: 1/8; 0.14; 1/5; 13%

Consider the arithmetic sequence 13, 16, 19, 22, 25, ...<br> What is the 60th term in the sequence?

Pavel [41]

Answer:

180

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help im behind my math class. pls

maks197457 [2]

Answer:

Please check the explanation.

Step-by-step explanation:

From the given diagram, we can observe that r and s are the two parallel lines intersected by the two transversal lines.

Therefore, the pairs of alternating interior angles formed by the two transversal lines are:

∠1 & ∠5

∠2 & ∠4

∠2 & ∠7

∠3 & ∠6

We know that alternating interior angles formed by a transversal line are congruent.

Thus,

∠1 = ∠5

∠2 = ∠4

∠2 = ∠7

∠3 = ∠6

Part a)

Given

m∠1 = 3x + 42

m∠5 = 8x - 8

As

∠1 = ∠5

So

3x + 42 = 8x - 8

flipe the equation

8x - 8 = 3x + 42

subtract 3x from both sides

8x - 8 - 3x = 3x + 42 - 3x

5x - 8 = 42

add 8 to both sides

5x - 8 + 8 = 42 + 8

5x = 50

divide both sides by 5

5x/5 = 50/5

x = 10.0000 (Rounded to four decimal places)

Thus, the value of x = 10.0000 (Rounded to four decimal places)

Part b)

Given

m∠6 = 12°

It is clear that angles ∠6 and angle ∠7 lie on a straight line.

Thus,

The sum of ∠6 and ∠7 is 180°.

∠6 + ∠7 = 180°

substituting m ∠ 6 = 12° in ∠6 + ∠7 = 180°

12° + ∠7 = 180°

subtract 12 from both sides

12° + ∠7 - 12° = 180° - 12°

∠7 = 168°

Thus, measure of angle ∠7 = 168°.

We already know that alternating interior angles formed by a transversal line are congruent.

∠7 and ∠2 are alternating interior angles.

Thus,

∠2 = ∠7

As ∠7 = 168°.

Therefore,

∠2 = 168°

Hence, we conclude that

∠2 = 168°

7 0

3 years ago

PLEASE HELP ASAP!!!!!!

statuscvo [17]

Answer:

24 sides

Step-by-step explanation:

a polygon cannot have a decimal number of sides, it is impossible

since the sum of these exterior angles in a regular polygon must equal 360 degrees. The maximum number of sides that would yield exterior angles that are integers is 360

because 360 ÷ 360 = 1.

4 0

2 years ago

How many more whole numbers can “n” satisfy in the inequality shown?

sesenic [268]

Two whole numbers
plssss mark as brilliant

6 0

3 years ago

2. Which of the following are terms of the series with nth term T-3n +17? a) 80 b) 170 c)217 d) 312 e) 278 f) 3566

pishuonlain [190]

Answer:

The correct options are a,b,e and f.

Step-by-step explanation:

It is given that the nth terms of the series is defined as

$T_n=3n+17$

Subtract 17 from both the sides.

$T_n-17=3n$

Divide both sides by 3.

$\frac{T_n-17}{3}=n$

The term Tₙ is a term of given series if n is a positive integer.

(a) The given term is 80.

$n=\frac{80-17}{3}=21$

Since n is a positive integer, therefore 80 is a term of given series.

(b) The given term is 170.

$n=\frac{170-17}{3}=51$

Since n is a positive integer, therefore 170 is a term of given series.

(c) The given term is 217.

$n=\frac{217-17}{3}=66.67$

Since n is not a positive integer, therefore 217 is a term of given series.

(d) The given term is 312.

$n=\frac{312-17}{3}=98.33$

Since n is not a positive integer, therefore 312 is a term of given series.

(e) The given term is 278.

$n=\frac{278-17}{3}=87$

Since n is a positive integer, therefore 278 is a term of given series.

(f) The given term is 3566.

$n=\frac{3566-17}{3}=1183$

Since n is a positive integer, therefore 3566 is a term of given series.

Thus, the correct options are a, b, e and f.

7 0

3 years ago