First question seems incomplete :
Answer:
40 ways
Step-by-step explanation:
Question B:
Number of boys = 6
Number of girls = 4
Number of people in committee = 3
Number of ways of selecting committee with atleast 2 girls :
We either have :
(2 girls 1 boy) or (3girls 0 boy)
(4C2 * 6C1) + (4C3 * 6C0)
nCr = n! ÷ (n-r)!r!
4C2 = 4! ÷ 2!2! = 6
6C1 = 6! ÷ 5!1! = 6
4C3 = 4! ÷ 1!3! = 4
6C0 = 6! ÷ 6!0! = 1
(6 * 6) + (4 * 1)
36 + 4
= 40 ways
Answer:
√7 units, √98 units
Step-by-step explanation:
Pythagorean theorem
a^2+b^2=c^2. So 9+b^2=16. So b^2=7. So b=√7
a^2+b^2=c^2. SO 49+49=c^2. So 98=c^2. So c=√98.
This symbol "∩" means intersection of both sets or what do both sets contain that are the same..
First set contains all numbers less than -5 and the other set contains all numbers greater than 5 so the sets don't overlap at all.
The solution set is empty ∅
Answer:
It is 17,18 and 19
Step-by-step explanation:
Consecutive numbers are
x, x+1, x+2
x+x+1+x+2=54
3x+3=54
-3 -3
3x=51
x=17
17
17+1=18
17+2=19
17, 18 and 19
