Question

Someone help me pleasw

Answer 1

$\sqrt[3]{-216}$

This can be rewritten as the following

$=\sqrt[3]{(-6)^3}$

By definition of the cube root,

$=-6$

Let me know if you have any questions, thanks!

Answer 2

$\bf \underline{Solution-}$

$\sf{ \sqrt[3]{ - 216} }$

$= \sf{ \sqrt[3]{ \bigg( \frac{1}{216} \bigg)} }$

$= \sf{ \sqrt[3]{ \bigg( \frac{1}{6} \bigg)^{3} } }$

$\sf{ = \bigg( \frac{1}{6} \bigg) ^{ \cancel3 \times \frac{1}{ \cancel3} } }$

$\sf = \bigg( \frac{1}{6} \bigg)^{1}$

$\sf = \frac{1}{6} \: \: \: \: Ans.$