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andrew-mc [135]
2 years ago
9

A point is plotted on the number line at 2 2/5 . A second point is plotted at −4 3/4 . What is the length of a line segment join

ing these points? Enter your answer as a simplified mixed number in the box.
Mathematics
2 answers:
Anastaziya [24]2 years ago
8 0

Answer:

  • 7 3/20

Step-by-step explanation:

<u>The distance is the absolute value of the difference of the coordinates:</u>

  • 2 2/5 - (-4 3/4) =
  • 2 2/5 + 4 3/4 =
  • 6 + 2/5 + 3/4 =
  • 6 + 8/20 + 15/20 =
  • 6 23/20 =
  • 7 3/20
Law Incorporation [45]2 years ago
5 0

Distance=

\\ \sf\longmapsto \left|2\dfrac{2}{5}-(-4\dfrac{3}{4})\right|

\\ \sf\longmapsto \left|2\dfrac{2}{5}+4\dfrac{3}{4}\right|

\\ \sf\longmapsto \left|\dfrac{12}{5}+\dfrac{19}{4}\right|

\\ \sf\longmapsto \left|\dfrac{48+95}{20}\right|

\\ \sf\longmapsto \left|\dfrac{143}{20}\right|

\\ \sf\longmapsto \left|7\dfrac{3}{20}\right|

\\ \sf\longmapsto 7\dfrac{3}{20}

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Answer:

\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\

Step-by-step explanation:

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note that i.i = j.j = k.k  =1

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proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\

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