All categories

3 years ago

-19 as a decimal Please answer ASAP! Thank you!

Mathematics

2 answers:

UNO [17]3 years ago

8 0

Answer:

-19 cannot become a decimal because it is a whole number, but what you can do is write it as a fraction: -19/1

Step-by-step explanation:

Sedbober [7]3 years ago

4 0

Answer:

if i could clarify it a bit more because right -19 cant be a decimal

Step-by-step explanation:

You might be interested in

Can someone answer this question plz

statuscvo [17]

That would be

1/3 * 3 ^3 + 14

= 1/3 * 27 + 14

= 9 + 14 = 23 (answer)

5 0

3 years ago

What is 39% of the Pacific Ocean

Cloud [144]

Answer:

.0039

Step-by-step explanation:

4 0

3 years ago

What is the solution to 2x-5 <12

bija089 [108]

Answer:

x < 10

Step-by-step explanation:

2x-8 <12

Add 8 to each side

2x-8+8 <12+8

2x< 20

Divide by 2

2x/2 < 20/2

x < 10

7 0

3 years ago

Read 2 more answers

(Marking Brainliest) What is the vertex form of the equation?<br><br>y = x^2 - 4x + 7

AysviL [449]

Step-by-step explanation:

y = x² - 4x + 7

the general vertex form is

y = m(x-h)² + k

to bring the part "x² -4x" to an expression of (ax + b)² we need to add 4, as "x² - 4x + 4" = (x - 2)².

and since we add 4 there, we need to subtract 4 overall again to keep the value of the expression the same :

y = x² - 4x + 4 + 7 - 4 = (x - 2)² + 7 - 4 = (x - 2)² + 3

and so, that is the vertex form :

y = (x - 2)² + 3

4 0

2 years ago

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

2 years ago