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svetlana [45]
2 years ago
13

What’s 25/36 as a decimal and percent please show work

Mathematics
1 answer:
9966 [12]2 years ago
3 0

Answer:

0.694444444

Step-by-step explanation:

just divide the top from the bottom-

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Use completing the square to solve x^2+6x=13
lara [203]

Answer:

x = -3 +/- square root(22)

Step-by-step explanation:

x = -b +/- square root(b^2 - 4ac) / 2a

ax^2 + bx + c = 0

these are both the quadratic formula but one is solved for the x and another for 0

a= 1

b= 6

c = -13

x= -6 +/- square root( 6^2 - 4(1)(13)) / 2(1)

x = -6 +/- sqrt( 36 + 52) / 2

x= -6 +/- sqrt (88) / 2

sqrt of 88 = 2 x sqrt (22)

divide 2 on each

x= -3 +/- sqrt (22)

8 0
2 years ago
Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
2 years ago
Which math expression means "the quotient of 39 and 13"?
Mkey [24]

Answer:  39.13

Step-by-step explanation:

:)

3 0
2 years ago
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If v lies in the first quadrant and makes an angle π/3 with the positive x-axis and |v| = 8, find v in component form.
e-lub [12.9K]

Answer:

amdlkmflakmflkmasdklmflkansdlkfwelkma;lkdsmlfdsnalkme;klamdlfsndldkanfdlknadlkfn;alkndflkandslknaslfknalkdfnladkfsnlkandslfkn

Step-by-step explanation:

3 0
3 years ago
Given f(x)=-x-1,find f(5)
Brut [27]

Answer:

f(5)=4

Step-by-step explanation:

f(5)=5_1=4

.....

3 0
3 years ago
Read 2 more answers
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