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Margaret [11]
3 years ago
11

Anastasia uses the equation p = 0.7(rh + b) to estimate the amount of take-home pay, p, for h hours worked at a rate of r dollar

s per hour and any bonus received, b.What is an equivalent equation solved for h?
Mathematics
2 answers:
poizon [28]3 years ago
8 0

Answer:

h=\frac{p-0.7b}{0.7r}


Step-by-step explanation:

The equation given is  p=0.7(rh+b)

Using distributive property on this, we can expand. Distributive property is given as:

a(b+c)=ab+ac

<em>Using this, we have:</em>

p=0.7rh+0.7b

<em>Rearranging and solving for  h  gives us:</em>

p-0.7b=0.7rh\\\frac{p-0.7b}{0.7r}=h

This is the formula with  h  as the subject.

Hitman42 [59]3 years ago
4 0
P = 0.7 ( r h  + b )
p = 0.7 r h + 0.7 b
0.7 r h = p - 0.7 b
h = ( p - 0.7 b ) / 0.7 r
h = 10 ( p - 0.7 b ) / 7 r
h = ( 10 p - 7 b ) / 7 r
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In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who
leonid [27]

Probability of a student playing both basketball and baseball is 7/28

Step-by-step explanation:

Step 1:

It is given the class has 28 students out of which 11 play basketball and 13 play baseball. It is also given that 11 students play neither sport.

Total number of students = 28

Students playing neither sport = 11

Students playing at least one sport = 28 - 11 = 17

Step 2:

Let N(Basketball) denote the number of students playing  basketball and N(Baseball) denote the number of people playing  baseball.

Then N(Basketball U Baseball) denotes the total number of students playing basketball and baseball and N(Basketball ∩ Baseball) denotes playing both basketball and baseball.

Since the number of students playing at least one sport is 17, N (Basketball U Baseball) = 17.

N (Basketball U Baseball) = N(Basketball) + N(Baseball) - N(Basketball ∩ Baseball)

N(Basketball ∩ Baseball) = N(Basketball) + N(Baseball) - N (Basketball U Baseball)

N(Basketball ∩ Baseball) = 11 + 13 - 17 = 7

Step 3:

Number of students playing both basketball and baseball = 7

Total number of students = 28

Probability of a student playing both basketball and baseball is 7/28

Step 4:

Answer:

Probability of a student playing both basketball and baseball is 7/28

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