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Svetllana [295]

2 years ago

7

How do you find the square roots of fractions. For example the square root of 9 over 16?

1 answer:

Pepsi [2]2 years ago

8 0

For the square root of a fraction, you could divide the fraction (top divided by the bottom) and then find the square root of the quotient. 9 divided by 16 is 0.5625, and the square root of 0.5625 is 0.75. / / / / For the other way to do it, you have to know that the square root of a fraction is the same thing as the square root of the top over the square root of the bottom. So the sqrt (9/16) = sqrt (9)/sqrt (16) = 3/4. (same thing as 0.75 .)

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Find the coordinates of the midpoint of the segment connecting points (-3,-6) and ( 2,5)

Pavlova-9 [17]

(x2 subtracted by x1 divided by 2, y2 subtracted by y1 divided by 2) is the midpoint formula.
(2-3/2, 5-6/2)= (-1/2, -1/2) which is the answer/

3 0

3 years ago

Jasmine buys the magic carpet on sale for $374. She saved $66 off the regular price. What percent was the price discounted?

Furkat [3]

Answer:

15%

Step-by-step explanation:

Let c represent the regular price of the carpet.

Then:

sale price = regular price less discount

$374 = c - $66

Adding $66 to both sides isolates (solves for) c:

$374 + $66 = c = $440. This is the regular price.

$66

---------- = 0.15 This is the fraction of the regular price by

$440 which the regular price is reduced.

Then the percentage of this discount was 0.15(100%) = 15%

8 0

2 years ago

Identify the line with an undefined slope

Fudgin [204]

Answer:

d. vertical line

Step-by-step explanation:

A line with an undefined slope is a vertical line

Slope is the change in y over the change in x

When the slope is undefined, it means that the x does not change, which is a vertical line

8 0

1 year ago

Read 2 more answers

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

2 years ago

Here are the scores that Jenna has

amid [387]

Answer:

the variance is 6.6

sry for not showing work

5 0

2 years ago