Answer:
Step-by-step explanation:
d(x)=√((x-2)2+(y-0)²)
=√((x-2)²+y²)
=√((x-2)²+(x-1)²)
=√(x²-4x+4+x²-2x+1)
=√(2x²-6x+5)
D=d²(x)=2x²-6x+5
The answer is B.
Hope it helps!
Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Lets x = # of hours Melania works at <span>office clerk
and y = </span># of hours Melania works as a <span>cashier
x + y = 38 so x = 38 - y
13x + 9.25y = 434
substitute </span> x = 38 - y into 13x + 9.25y = 434
13x + 9.25y = 434
13(38 - y) + 9.25y = 434
494 - 13y + 9.25y = 434
-3.75y = -60
y = 16
x = 38 - y so x = 38 - 16 = 22
answer
Melania works at office clerk = 22 hours
Melania works as a cashier = 16 hours
