Step-by-step explanation:
Let us consider the task to find the angle between vectors ES and EJ (the first letters are taken to name the vectors).
\overrightarrow{ES} = (4;4) - (4; -3) = \overrightarrow{(0; 7)}
ES
=(4;4)−(4;−3)=
(0;7)
\overrightarrow{EJ} = (-5; -4) - (4; -3) = \overrightarrow{(-9; -1)}
EJ
=(−5;−4)−(4;−3)=
(−9;−1)
cos \alpha=\frac{\overrightarrow{ES}*\overrightarrow{EJ}}{|\overrightarrow{EJ}|*|\overrightarrow{ES}|}cosα=
∣
EJ
∣∗∣
ES
∣
ES
∗
EJ
cos(a) = (0*(-9)+7*(-1)) / (7*9.055) = -0.11043;
a = 96,34°
Solution: 96 degrees.
XD do what kind of question is this.
Answer:
X=-10
Step-by-step explanation:
Flip it
7X=-70
Divide both sides by 7
7x/7= -70/7
To solve these, I like to write it out in expanded form for each rectangle.
Starting from left to right:
(12*7)+(12*5)+(12*7)+(7*5)+(12*5)+(7*5)
It can also be written as:
2(12*7)+2(12*5)+2(7*5)
This equals 358cm^2
It is squared because it is a result of multiplying 2 dimensions: length*width.