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Digiron [165]
2 years ago
8

How can I sign up for one on one tutoring and what is the cost

Mathematics
1 answer:
kati45 [8]2 years ago
5 0

when you click on the tutoring tab it will show you all the details

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16.43 7 rounded to the nearest tenth is 16.4 true or false is it true
storchak [24]
It is true. here is how........
4-0 is rounding down
5-9 is rounding up
when rounding to the tenths place you look at the hundredths place to find the answer.
3 0
3 years ago
Sample Response: The two conditional probabilities are not equal because each has different given events. P(A|D) has event D as
Ivan

The conditional probability illustrates that's there's a 2/8 that the event A occurs.

<h3>How to illustrate the probability?</h3>

It should be noted that probability simply means the likelihood of the occurence of an event.

In this case, it can be delivered that P(AID) and P(DIA) aren't equal.

Hence, P(D|A) has event A as its given event, resulting in 2/8 for a probability.

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

7 0
2 years ago
It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
Please help me solve this I forgot how to
RideAnS [48]
2.5 

hope it helps//...,d/cmn/lsjdhc;ljwknefv


4 0
3 years ago
ron walks 0.5 mile on track on the track in 10 minutes. stevie walks 0.25 mile on the track in 6 minutes. find the unit rate for
guapka [62]
Ron walks 1/2 mile in 10 minutes. There are six 10 minute intervals in an hour 60 divided by 10 is 6. So, therefore he can walk 1 mile in 20 minutes, 1/3 of an hour and a total of 3 miles per hour.
3 x 20 = 60.

Stevie walks 1/4 of a mile in 6 minutes, so that's 12 minutes to walk 1/2 mile. 60/12=5
Stevie can walk 5 half miles which transfers to 2 1/2 miles per hour.
8 0
3 years ago
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