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krok68 [10]
3 years ago
5

What is the logical form of:

Mathematics
1 answer:
exis [7]3 years ago
4 0
Basically saying u can divide any number by 2 and 3 but not 4
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1/6 + 2/3 tell me wat it is pls​
Nutka1998 [239]

Answer: 5/6

Step-by-step explanation:

2/3=4/6

1/6 + 4/6 = 5/6

5 0
3 years ago
Read 2 more answers
What is the speaker’s viewWhen I heard the learn'd astronomer;
Phantasy [73]
A. He feels tired and sick because the focus on the mechanical measurements of stars is not satisfying to him.<span>
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3 years ago
The following shows the monthly sales in units of six salespersons before and after a bonus plan was introduced. At 95% confiden
saw5 [17]

Answer:

it is clear that at 95% confidence that the bonus plan has increased the sales significantly, because if we observe you will notice that sales after is greater than sales before in all six cases.

Step-by-step explanation:

A 95% confidence interval as we have above is the range of values that we can say with utmost certainty and confidence that 95% chance it contains the true mean of the population. in other words we can say that a  95% confidence interval defines a range of values that you can be 95% certain contains the population mean.

4 0
3 years ago
K=mv^2/2 solve for v
matrenka [14]

Answer: v=\sqrt[]{\frac{2K}{m} }

Step-by-step explanation:

K=\frac{mv^2}{2}

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

2*K=\frac{mv^2}{2}*2

2K=mv^2

Divide by m to isolate v^2.

\frac{2K}{m}=\frac{mv^2}{m}

\frac{2K}{m} =v^2

To eliminate the square and isolate v, extract the square root.

\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}

\sqrt[]{\frac{2K}{m} }=v

let's rewrite it in a way that v is in the left side.

v=\sqrt[]{\frac{2K}{m} }

4 0
3 years ago
The volume of a cube 512 cubic inches. What is the length of the cube?
aleksandr82 [10.1K]

Answer:

I believe it is 8in

Step-by-step explanation:

someone correct me if I'm wrong

8 0
3 years ago
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