What is the approximate value of 113−−−√ to the nearest tenth?
1 answer:
Answer:
10.6
Step-by-step explanation:
1. First, we need to find which digits √(113) is between, and that would be 10 and 11.
2. Okay, so √(113) is between 10 and 11, meaning 113 is between 100 and 121.
3. Since 113 is a little over half between 100 and 121, let's multiply 10.6 by 10.6 to see how close we are to 113:
4. 112.36 is pretty close to 113, therefore, the dot on the number-line should be placed at 10.6.
You might be interested in
Lagrange multipliers:
(if 
)
(if )
(if 
)
In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force 
, so the point we found is the only extremum.
In the first octant, we assume
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
We also need to check the boundary of the region, i.e. the intersection of