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Nookie1986 [14]
3 years ago
11

Multiply 6.23 and 2.8 the product is_________ (with solution please)

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Step-by-step explanation:

please mark me as brainlest

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Which characteristic does the graph display?
Leto [7]

If the factors of the polynomial are (x - 2), (x), and (x + 2). Then the equation of the graph will be (x³ - 4x).

<h3>What is the equation of the graph?</h3>

The solutions of the graph are 2, 0, and negative 2.

Then the factor can be given as

(x - 2), (x), and (x + 2)

Then the product of the factor will be given below.

(x - 2) × (x) × (x + 2)

x (x² - 4)

x³ - 4x

More about the equation of the graph link is given below.

brainly.com/question/1971145

#SPJ1

4 0
2 years ago
Which of the following best describes the set of all numbers of the form a+bi where a and b are any real numbers and i equals sq
Andrei [34K]
<h3>Answer: B) Complex numbers</h3>

Complex numbers are always in the form a+bi with 'a' and 'b' as real numbers.

If b = 0 and 'a' is nonzero, then a+bi = a+0i = a which is strictly a real number

If a = 0 and b is nonzero, then a+bi = 0+bi = bi indicating that the number is now purely imaginary

6 0
3 years ago
HELP ME PLS AND THANK YOU
Anna35 [415]
X= - 7/2
Hope this helps! :)
3 0
3 years ago
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Help me please!!! 45 points to whoever helps!!
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7 0
3 years ago
Which is the solution to (8.5 x 103)(2 x 105) expressed in scientific notation?
kenny6666 [7]

We have been given an expression (8.5\times 10^3)(2\times 10^5). We are asked to find the solution to our given expression expressed as scientific notation.

Let us simplify our given expression.

Using exponent property a^m\cdot a^n=a^{m+n}, we will get:

8.5\times 2\times 10^3\times 10^5

17\times 10^{3+5}

17\times 10^{8}

Now to write our answer in scientific notation, we need our 1st multiple between 1 and 10. So we will rewrite our expression as:

1.7\times 10\times 10^{8}

1.7\times 10^{1+8}

1.7\times 10^{9}

Therefore, our required solution would be 1.7\times 10^{9}.

8 0
3 years ago
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