![a\cdot a\cdot a=216\\\\a^3=216\to a=\sqrt[3]{216}\\\\\boxed{a=6}\\\\\text{Substitute}\ b\cdot c=52\ \text{to the second expression}\ a\cdot b\cdot c=96:\\\\abc96\ \wedge\ bc=52\to a(52)=96\qquad\text{divide both sides by 52}\\\\a=\dfrac{96}{52}\to a=\dfrac{24}{13}\neq6](https://tex.z-dn.net/?f=a%5Ccdot%20a%5Ccdot%20a%3D216%5C%5C%5C%5Ca%5E3%3D216%5Cto%20a%3D%5Csqrt%5B3%5D%7B216%7D%5C%5C%5C%5C%5Cboxed%7Ba%3D6%7D%5C%5C%5C%5C%5Ctext%7BSubstitute%7D%5C%20b%5Ccdot%20c%3D52%5C%20%5Ctext%7Bto%20the%20second%20expression%7D%5C%20a%5Ccdot%20b%5Ccdot%20c%3D96%3A%5C%5C%5C%5Cabc96%5C%20%5Cwedge%5C%20bc%3D52%5Cto%20a%2852%29%3D96%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%2052%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B96%7D%7B52%7D%5Cto%20a%3D%5Cdfrac%7B24%7D%7B13%7D%5Cneq6)
a = 6 and a = 24/13 FALSE!!!
<h3>Answer: NO SOLUTION.</h3>
Answer:
(A) No solution
(B) One solution
(C) One solution
(D) One solution
(E) No solution
Please tell me if this is incorrect. I hope this helps!
The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.
x^3+5x^2-6x-30
(x^3+5x^2)+(-6x-30)
x^2(x+5)+(-6x-30)
x^2(x+5)-6(x+5)
(x^2-6)(x+5)
-------------
Answer: (x^2-6)(x+5)
It would be 3 and 1 one hundredth.
Answer:

or

Step-by-step explanation:
Let
x ----> the additional pounds of plant food needed for the landscaper
we know that
The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed
so
The linear equation that represent this problem is

Convert mixed number to an improper fractions


Substitute in the expression above

solve for x
Multiply by (4*6) both sides to remove the fractions

Combine like terms left side

subtract 46 both sides


Divide by 24 both sides

simplify

Convert to mixed number
