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Ksju [112]
2 years ago
6

5. The mean exam score for the first group of twenty examinees applying for a security job is 35.3 with a standard deviation of

3.6.
The mean exam score for the second group of twenty examinees is 34.1 with a
standard deviation of 0.5. Both distributions are close to symmetric in shape.

a. Use the mean and standard deviation to compare the scores of the two groups.

b. The minimum score required to get an in-person interview is 33. Which group
do you think has more people get in-person interviews?
Mathematics
1 answer:
skad [1K]2 years ago
3 0

Answer:The mean exam score for the first group of twenty examinees applying for a security

job is 35.3 with a standard deviation of 3.6.

The mean exam score for the second group of twenty examinees is 34.1 with a

standard deviation of 0.5. Both distributions are close to symmetric in shape.

Use the mean and standard deviation to compare the scores of the two groups.

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Can someone please help me
scoundrel [369]
I think it is c. but i'm not sure
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3 years ago
After the drama club sold 100 tickets to a show, it had $300 in profit. After the next show, it had sold a total of 200 tickets
Alinara [238K]

Answer:


Option a :  y-300 = 4(x - 100)


Step-by-step explanation:

Given :

The drama club sold 100 tickets to a show, it had $300 in profit.

The next show, it had sold a total of 200 tickets and had a total of $700 profit.

To Find :  Equation models the total profit, y, based on the number of tickets sold, x

Solution :

For 100 tickets he had $300 in profit .


⇒ (x_{1} ,y_{1})=(100,300)


For 200 tickets he had $700 in profit .


⇒ (x_{2} ,y_{2})=(200,700)


We will use point slope form i.e.


y-y_{1} = m(x - x_{1}) --(A)


Now, to calculate m we will use slope formula :


m = \frac{y_{2} -y_{1} }{x_{2}-x_{1}  }


m = \frac{700 -300}{200-100}


m =4


Now, putting values in (A)


y-300 = 4(x - 100)


Thus Option a is correct i.e. y-300 = 4(x - 100)




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See the graph in the attached image.

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