Answer:
Step-by-step explanation:
We are told that the perimeter is 48 = 2L + 2W. This reduces to
24 = L + W. Next, substitute, one by one, the 3 widths 10 cm, 3.6 cm and w cm:
a) If W = 10 cm, 24 = L + W becomes 24 = L + 10, or L = 14 cm
b) If W = 3.6 cm, 24 = L + W becomes 24 = L + 3.6, or L = 20.6 cm
c) If W = w, 24 L + W becomes 24 = L + w, so that L = (24 - w) cm
Answer:
270
Step-by-step explanation:
you will times 6 by 45
Answer: Choice D

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Explanation:
The left portion is the interval (-∞, -2)
This is a shorthand way of saying 
The curved parenthesis says "do not include this endpoint as part of the solution set". Note the open hole at x = -2 in the diagram.
In contrast, the value x = 4 is included (due to the filled in circle), so we use a square bracket for this endpoint. Therefore, the right-hand portion is represented by [4, ∞) which translates to 
Negative and positive infinity will always use a parenthesis, and never a square bracket. This is because we can only approach infinity but never reach it, so we cannot include it as an endpoint.
All of this builds up to the full interval notation to be 
The only square bracket is near the 4; everything else is a curved parenthesis. This is why choice D is the final answer.
In this question , it is given that we have a cylinder with with a radius of 9 and a surface area of approximately 791.68 units square.
The formula of surface area of cylinder is

Substituting the values of A and r, we will get

So the height of the cylinder is 5 units .
The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.
Rest Area=((1+7)/2, (-4+1)/2)
Rest Area=(4, -1.5)
The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.
d^2=(x2-x1)^2+(y2-y1)
d^2=(7-1)^2+(1--4)^2
d^2=36+25
d^2=61
d=√61 and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:
D=5.38√61 mi
D≈42.02mi (to nearest hundredth of a mile)