I'm sorry I'm not home so I can't tell you the answer to this but what I can tell you is put together the xy and then put together the -13-20. Hope this helps.
Answer:
7a^4b^3
Explanation/Steps to solve:
First you separate 49 and 21 from the variables. Then you find their GCF.
The GCF of 49 is 21 is 7.
Then you find the GCF of the variables.
a^4b^3 and a^4b^5
how many As and Bs do they have in common?
both variables have 4 As and both have 3 Bs. <u><em>It can't be 5 Bs since the other variable only has 3. 3 is less than 5 which means that there can be a 3 in the other variable (b^5).</em></u>
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So we rewrite how much As and Bs they have.
4 As = a^4
3 Bs = b^3
---> a^4b^3
then we combine both the GCF of the numbers and the variables,
7a^4b^3
Answer:
2736 square feet
Step-by-step explanation:210 minus 18(9 times 2 )equals 192 then 192 divided by 4 (4 because 4 side )equals 48 (48 is the width) to get the length 48 plus 9 equals 57 (57 is the length) to get the area multiply length times width so 57 times 48 equals 2736 square feet
The GCF (greatest common factor) of both of these numbers is 4, so if you divide the numerator and denominator by 4, you get 3/5.
