Answer:
32
Step-by-step explanation: xbcjxnszHJCGewupearl had some beads She used 3/5 of them to make bracelets and 1/4 of the remainder to decorate her sweater if she had 300 beads left how many beads did she have at first jdks
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
317
Step-by-step explanation:
I did this on khan academy
The answer to your question is 2250
= -1/2- (-2/5)
= -1/2 + 2/5
find common denominator (2 goes in 10 five times; 5 goes in 10 twice)
= -(5*1)/10 + (2*2)/10
= -5/10 + 4/10
= -1/10
Hope this helps! :)