<h2>Hey there!</h2>
<h3>At first we have find the value of "y",</h3>
<h3>Finding the value of "y"</h3>
Here,
8x + y = 23 - 10x - y = - 27
10(8x + y) = 23 × 10 8 (- 10x - y) = - 27 × 8
80x + 10y = 230 ---> (i) - 80x - 8y = - 216 ----> (ii)
<h3>By elimination method,</h3>
<h3>Equation (i) - (ii)</h3>
(80x + 10y) - (-80x - 8y) = 230 - (-216)
=> 80x + 10y + 80x + 8y = 230 + 216
=> 10y + 8y = 446
=> 18y = 446
=> y = 446/18
=> y = 24.7
<h3>Putting the value of "y" in Equation (i)</h3>
80x + 10y = 230
=> 80x + 10 × 24.7 = 230
=> 80x + 247 = 230
=> 80x = 230 - 247
=> 80x = -17
=> x = -17/80
=> x = - 0.21
<h3>Therefore the values of "x" and "y" are</h3>
x = -0.21 and y = 24.7
<h2>Hope it helps </h2>
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>
Answer:
V = 235.5
Step-by-step explanation:
V=π r^2 h
V = pi 5^2 3
V = pi 25 3
V = 3.14 * 75
V = 235.5
Answer: Dominant. The answer is dominant.
