I think it's 8925 since you would do 85000 times .105
Answer:
11 13 15 17 19
Step-by-step explanation:
We will solve this word problem using 2k+1 which is one of the general forms of an odd integer.
Let 2k+1 be the first odd integer.
(2k+1) + (2k+3) + (2k +5) = (2k+7) + (2k +9) + 3 (the +3 is to accommodate for the left side being 3 more than the right)
Solve for k
6k + 9 = 4k + 19
6k - 4k + 9 = 4k-4k + 19
2k + 9 = 19
2k + 9 - 9 = 19 - 9
2k = 10
2k/2 = 10/2
k = 5
To get the first digit in the series plug in 5 for k
2k+1
2(5) + 1
10 + 1 = 11
So our series is 11, 13, 15, 17, 19
Let's test it.
11 + 13 +15 = 39
17 + 19 = 36
So we are correct, the first 3 integers are 3 more that the sum of the last 2.
Thirty-one<span> is the closest square to 1000</span>
Answer:
See below for answer.
Step-by-step explanation:
RP/RT =RQ/RS Given
∠R = ∠R
ΔPQR similar to Δ TSR If the measures of two sides of a triangle are proportional to the measures of two corresponding sides of another triangle and their included angles are congruent, then the triangles are similar.
Given that the situation has been modeled by the formula:
B=1000e^(kt)
given that B=8520 after t=15 min
then the value of k will be solved as follows:
plugging in the values in the formula and solving for k
8520=1000e^(15k)
8.52=e^(15k)
solving for k
15k=ln(8.52)
hence
k=ln(8.52)/15
k=0.1428
k=0.143
