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timurjin [86]
4 years ago
7

Give me an example of an irrational number that is greater than 10

Mathematics
1 answer:
Pavel [41]4 years ago
5 0

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of \dfrac{p}{q}, where, q\neq 0, p,q are integers.

For example: \sqrt{2}\sqrt{3},\pi, 1.263689...,etc..

We know that square of 10 is 100. So, square root of any prime number is  an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number =\sqrt{101}

Therefore, \sqrt{101} is an irrational number that is greater than 10.

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PLEASE HELP! You do not have to answer all questions but can someone explain to me on where I am even suppose to begin? I don't
Gre4nikov [31]

Step-by-step explanation:

For problems 1 through 15, evaluate the function at the given x value.

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Then, match each answer with the corresponding letter.

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6 0
3 years ago
Factor x3 – 7x2 – 5x 35 by grouping. what is the resulting expression? (x2 – 7)(x – 5) (x2 – 7)(x 5) (x2 – 5)(x – 7) (x2 5)(x –
mars1129 [50]

The factored expression ofx^3 - 7x^2 -5x +35 is (x^2 - 5)(x - 7)

<h3>What is an expression?</h3>

An expression is an algebraic term used for a mathematical statement that includes addition subtraction multiplication and division

x^3 – 7x^2 – 5x + 35

factor the given equation

x^2(x – 7) – 5(x - 7)

Factor out x - 7

(x^2 - 5)(x - 7)

Therefore, the factored expression is (x^2 - 5)(x - 7)

To learn more about the factored expression visit:

brainly.com/question/723406

7 0
2 years ago
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