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timurjin [86]
4 years ago
7

Give me an example of an irrational number that is greater than 10

Mathematics
1 answer:
Pavel [41]4 years ago
5 0

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of \dfrac{p}{q}, where, q\neq 0, p,q are integers.

For example: \sqrt{2}\sqrt{3},\pi, 1.263689...,etc..

We know that square of 10 is 100. So, square root of any prime number is  an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number =\sqrt{101}

Therefore, \sqrt{101} is an irrational number that is greater than 10.

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Step-by-step explanation:

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3 years ago
For a person who has a mass 60 kg , calculate the weight in Newton if 1 In equals 4.45 N , then what is the person's weight in p
wel

Answer:

The answer to your question is  a) 588.6 N   b) 132.3 N

Step-by-step explanation:

Data

mass = 60 kg

weight = ?

Process

1.- Write the formula of weight

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gravity = 9.81 m/s²

2.- Substitution

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3.- Result

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4.- Convert Newtons to Pounds

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4 0
4 years ago
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Step-by-step explanation:

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