Answer:
The number of times organism B's population is larger than organism A's population after 8 days is 32 times
Step-by-step explanation:
The population of organism A doubles every day, geometrically as follows
a, a·r, a·r²
Where;
r = 2
The population after 5 days, is therefore;
Pₐ₅ = = 32·a
The virus cuts the population in half for three days as follows;
The first of ta·2⁵ he three days = 32/2 = 16·a
The second of the three days = 16/2 = 8·a
After the third day, Pₐ = 8/2 = 8·a
The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;
P₈ = a·2⁸ = 256·a
Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times
Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.
Hope this helps you out! :)
Also, it's OK! This was actually pretty hard to figure out!
≈ 54.97