Round to the nearest tenth for 69.08, 43.96, 39.564 please show how to do it

2 answers:

5 0

Answer: 69.1, 44.0,39.6

explanation: you look at the value next to the tenths place which is the hundredths and if the number is above a five you add one to the tenth place but if the number is under 5 you keep the tenths place the same

Wittaler [7]3 years ago

5 0

Answer:

69.08 ⇒ nearest tenth

To round 69.08 to the nearest tenth, 0 is in the tenths place and 8 is in the hundredths place. Since the digit in the hundredths place (8) is greater than 5, add 1 to the digit in the tenths place (0).

1 + 0 = 1, so the digit in the tenths place becomes 1 & the digit in the hundredths place is dropped.

∴ 69.08 ≈ 69.1 (corrected to the nearest tenth)

43.96 ⇒ nearest tenth

To round 43.96 to the nearest tenth, 9 is in the tenths place and 6 is in the hundredths place. Since the digit in the hundredths place (6) is more than 5, add 1 to the digit in the tenths place (9), add 1 to the digit in the tenths place (9). This will also add 1 to the whole number part and make the fractional part 0.

1 + 9 = 10

∴ 43.96 ≈ 44 (corrected to the nearest tenth)

39.564 ⇒ nearest tenth

To round 39.564 to the nearest tenth, 5 is in the tenths place and 6 is in the hundredths place. Since the digit in the hundredths place (6) is more than 5, add 1 to the digit in the tenths place (5), add 1 to the digit in the tenths place (5).

1 + 5 = 6, so the digit in the tenths place becomes 6 & the digit in the hundredths and thousandths place is dropped.

∴ 39.564 ≈ 39.6 (corrected to the nearest tenth)

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When we test Upper H 0: muequals0 against Upper H Subscript a: mugreater than0, we get a P-value of 0.03. a. What would the

Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

Step-by-step explanation:

The hypothesis provided is:

$H_{0}: \mu = 0\\ H_{a} : \mu > 0$

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

$p-value = 0.03 < \alpha = 0.10$