the length of a new rectangular playing field.is 9 yards longer than quadruple the width, If the perimeter of the rectangular pl
1 answer:
The dimensions of a playing field that has a perimeter of 528 yards are:
- Length = 213 yards
- Width = 51 yards
<em><u>Recall:</u></em>
Perimeter of a rectangle = 2(L + W)
We can represent the length and width using variables to form algebraic expressions as follows:
- Let W represent the width
- Width = W
- Length = (4W + 9) yards
- Perimeter = 528 yards
<em>The following </em><em>equation</em><em> would be created to find the value of </em><em>W:</em>
2(L + W) = Perimeter
- Substitute
2[(4W + 9) + W} = 528
- Solve for W
- Add like terms
- Subtract 18 from each side
- Divide both sides by 10
W = 51
<u><em>Width is the </em></u><u><em>rectangular </em></u><u><em>playing field is </em></u><u><em>51 yards</em></u>
<u><em /></u>
<u>Find the </u><u>Length</u><u>:</u>
Length = (4W + 9) yards
- Plug in the value of W
Length = 4(51) + 9 = 213 yards
Therefore, the dimensions of a playing field that has a perimeter of 528 yards are:
- Length = 213 yards
- Width = 51 yards
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