Answer:
2369
Step-by-step explanation:
Answer:
Isosceles Triangle
Step-by-step explanation:
Triangle ABC has vertices A(-5, -1), B(5, -1), and C(0, -4). Is it scalene, isosceles or equilateral?
We solve this question using vertices formula:
√(x2 - x1)² + (y2 - y1)² when given vertices: (x1, y1) and (x2 , y2)
For Side AB
A(-5, -1), B(5, -1)
AB = √(5 - (-5))² + (-1 -(-1))²
AB= √(5 + 5)² + (-1 + 1)²
AB = √10² + 0
AB = √100
AB = 10 units
For Side BC
B(5, -1), C(0, -4)
BC = √(0 - 5)² + (-4 -(-1))²
BC = √-5² + (-4 + 1)²
BC = √25 + -3²
BC = √25 + 9
BC = √34
For Side AC
A(-5, -1), C(0, -4).
AC = √(0 - (-5))² + (-4 - (- 1)²
AC = √5² + -3²
AC = √25 + 9
AC = √34
Therefore this triangle is an isosceles triangle because 2 of its sides (AC and BC ) are equal to one another
Answer:
Denote O as center of circle, draw OA, OC.
As property of tangent line from outside of circle (angle OAD = angle OCD = 90 deg):
=> AOC + D = 180
Moreover, angle AOC = 2 x angle B = 2 x 65 = 130
=> D = 180 - 130 = 50 deg
Hope this helps!
:)
Answer: I believe the correct answer is A. Because 2/3 is negative so it belongs on the negative side of the number line. And 5/3 is positive so it belongs on the positive of the number line.
* Hopefully this helps:) Mark me the brainliest:)
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The answer is -16
Step by step explanation:
the expression of this equation is √4x=-32, so first, we would find the square root of 4, which is 2. so now we have 2x=-32. Next we want to divide 2 from both sides, which gives us our final result: x=-16. So our answer is -16.