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Nadya [2.5K]
2 years ago
10

The process by which information gets into memory storage is

Computers and Technology
1 answer:
Kay [80]2 years ago
7 0

Answer:

That is the first step and it is called encoding process.

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Engineers at Edison Laboratories developed a _____ strip that allowed them to capture sequences of images on film.
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Answer:

Kinetoscope

Explanation:

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Why is continual user involvement a useful way to discover system requirements? Under what conditions might it be used? Under wh
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continual user involvement gives the flexibility to analyze the requirements in right direction. because there is continuous meetings with the end user and he can provide right direction or avoids wrong interpretation of the requirement

Explanation:

continual user involvement is useful when we are following agile methodology where we are building complex systems. it is not useful for simple sytems and following waterfall methodology

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Apple Final Cut Pro is a digital video editing program that is available for Macs with OS X version 10.4 or later.
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That's actually true lol

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Data silos are often associated with ________________.
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Answer:

Option b the development of one or a few related analytics applications.

Explanation:

Data silo is the isolated information in an organization which is not shared across different departments. Data silo could exist because one department in an organization may not see the necessity to share information to other department. Or the information is deemed as unique data which is dedicated  to develop one or a few very specific analytics applications.  Data silos should be minimized if an organization intends to develop a data analytics system that support in enterprise wide level.

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3 years ago
What is output? public class MathRecursive { public static void myMathFunction(int a, int r, int counter) { int val; val = a*r;
ycow [4]

Answer:

The output of the program is:

2 4 8 16 32 64 End

Explanation:

See attachment for proper presentation of the program

The program uses recursion to determine its operations and outputs.

The function is defined as: myMathFunction(int a, int r, int counter)

It initially gets the following as its input from the main method

a= 1; r = 2; counter = 0

Its operation goes thus:

val = a*r; 1 * 2 = 2

Print val; Prints 2

if (counter > 4) { System.out.print("End"); } : Not true

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 2; r = 2; counter = 1

val = a*r; 2 * 2 = 4

Print val; Prints 4

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 4; r = 2; counter = 2

val = a*r; 4 * 2 = 8

Print val; Prints 8

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 8; r = 2; counter = 3

val = a*r; 8 * 2 = 16

Print val; Prints 16

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 16; r = 2; counter = 4

val = a*r; 16 * 2 = 32

Print val; Prints 32

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 32; r = 2; counter = 5

val = a*r; 32 * 2 = 64

Print val; Prints 64

if (counter > 4) { System.out.print("End"); } : True

<em>This prints "End"</em>

So; the output of the program is:

2 4 8 16 32 64 End

3 0
2 years ago
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