3 years ago

Find the missing dimension of the prism. Volume = 532 in. 3 19 in

Mathematics

1 answer:

I am Lyosha [343]3 years ago

3 0

Subtract them but turn 532 into a decimal

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This my test question I'm 100 bad at math 2b2+16b+49÷2b+4

krek1111 [17]

2b^2 + 81/2 b + 4

basically 2b^2 + 16b + 49/2 b + 4
= (2b^2) + 16b+49/2b) + (4)
= 2b^2 + 81/2 b + 4

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3 years ago

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ludmilkaskok [199]

The total money spent for the Dinner and Dessert is $22 so to figure out how much was spent on the taxi ride you're going to want to subtract $22 from $31 (31 = x + 22) or (31 - 22 = x).

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kennys weight is 6/7 times melvins weigh what is the ratio of kennys weight to melvints weight give your answer in fraction form

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3 years ago

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vlada-n [284]

Answer:

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3 years ago

What is the following product ^3sqrt16x^7*^3sqrt12x^9

hichkok12 [17]

Answer:

4x^5\sqrt[3]{3x}

Step-by-step explanation:

Given

$\sqrt[3]{16x^7}\left(\sqrt[3]{12x^9}\right)\\\sqrt[3]{4^{2} x^7}\sqrt[3]{4(3)x^9}\\ 4^\frac{2}{3} . x^\frac{7}{3} . 4^\frac{1}{3} . 3^\frac{1}{3} . x^\frac{9}{3}\\ 4^\frac{2+1}{3} . 3^\frac{1}{3}. x^\frac{9+7}{3} \\4^\frac{3}{3} . 3^\frac{1}{3}. x^\frac{16}{3}\\ 4\sqrt[3]{3x^16}$

$4\sqrt[3]{3} . x^\frac{16}{3} \\4\sqrt[3]{3} . x^\frac{15}{3} .x^\frac{1}{3} \\4\sqrt[3]{3} . x^5 .x^\frac{1}{3} \\4x^5\sqrt[3]{3x}$ !

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3 years ago

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Find the missing dimension of the prism. Volume = 532 in. 3 19 in​

Find the missing dimension of the prism. Volume = 532 in. 3 19 in