is there a picture we can use to understand this?
Answer:
An old bone contains 80% of its original carbon-14 in 1844.6479 years
Step-by-step explanation:
We know that
half life time of C-14 is 5730 years
so, h=5730
now, we can use formula

we can plug back h
and we get

An old bone contains 80% of its original carbon-14
so,
P(t)=0.80Po
we can plug it and then we solve for t





So,
An old bone contains 80% of its original carbon-14 in 1844.6479 years
DF congruent to AC and EF is common side
Answer:
BC = 35 units
Step-by-step explanation:
fjtcjcuttiftfitcurcuruchrxruxfxurdurux
Answer:
(x+5/2)^2 = 0
Step-by-step explanation:
4 x^{2} +20x +25 =0
Divide by 4
4/4 x^{2} +20/4x +25/4 =0
x^2 +5x +25/4 =0
Subtract 25/4 from each side
x^2 +5x +25/4 -25/4 =-25/4
x^2 +5x =-25/4
Take the coefficent of x
5
Divide by 2
5/2
Square it
25/4
Add it to each side
x^2 +5x +25/4 =-25/4+25/4
(x+5/2)^2 = 0
Take the square root of each side
x+5/2 = 0
x = -5/2