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Andrew [12]
3 years ago
8

Find the missing side length.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

5cm+6cm=11cm

Step-by-step explanation:

Adding the two,

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Could someone please take a look to see If I got my Math problem correct, Thank you.
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Yes, that looks correct!
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4 years ago
Can you solve this equation 13m-22=9m-6
kati45 [8]


13m-22=9m-6

13m-9m-22=-6

4m-22=-6

4m=-6+22

4m=16

m=16/4

m=4


<em>Therefore, m is 4</em>

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3 years ago
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Giving brainliest please help and understand this step by step
MA_775_DIABLO [31]

Answer:

3,813.33 \:  {cm}^{3}

Step-by-step explanation:

Volume of the space that is not occupied = Volume of cube shaped box - volume of soccer ball

=  {20}^{3}  -  \frac{4}{3}  \times 3.14 \times  {10}^{3}  \\  \\  = 8000 -  \frac{4}{3}  \times 3.14 \times  1000 \\  \\   = 8000 -  \frac{4}{3}  \times 3140 \\  \\  = 8000 -  \frac{12560}{3}  \\  \\  = 8000 - 4,186.66667 \\  \\  = 3,813.33333 \\  \\  = 3,813.33 \:  {cm}^{3}

5 0
3 years ago
Which shows like terms from the expression? 9 + 5 + 7x2 + 3 x2y + 2x2 3 x2y and 2x2 7x2, 3 x2y, and 2x2 9 and 5 2, 3, 5, and 9
snow_lady [41]

Answer:

9 and 5.

Step-by-step explanation:

So we have the expression:

9+5+7x^2+3x^2y+2x^2

In order to combine like terms, the variables must be <em>exactly</em> the same: not one less, not one more.

3x²y and 2x² <em>cannot</em> be combined because the first value has a y.

7x², 3x²y, and 2x² also <em>cannot </em>be combined because the second value has a y.

9 and 5 is the only one that can be combined because they are just integers. They can be added to be 14.

2, 3, 5, and 9 <em>cannot</em> be combined because the 2 and the 3 are tied to the variables as coefficients. They are not constants.

5 0
3 years ago
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