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algol [13]
4 years ago
6

Which of the following statements is true if m ZE= m 2 Y and m2F = m2X?

Mathematics
1 answer:
const2013 [10]4 years ago
8 0
Jsjajwjwjjwjwwkwjkwkw
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How do you write a ratio as a percent
Vikentia [17]
Take the ratio
4:8
Convert it to a fraction
4/8
Divide
.5
Multiply by 100 and add a % sign
50%
3 0
4 years ago
What is the value of 8 in 8.644.58
Maslowich
So for the first 8, we need to find the value. The way I would find the value would be to find it's place value. So I know that the 8 is in the millionths period. So the value of the eight would be in the millionths. So I think it would be 8,000,000. So that would be the answer. The 8's value is 8,000,000 because of it being in the millionths period.

Hope that helped! :D
7 0
4 years ago
Explain why sin^-1(sin(3pi/4))does not equal 3pi/4 when y=sin x and y=sin^-1 x are inverses.
Fofino [41]

Because they're not inverses, not exactly. \sin x is not invertible on its entire domain because it's not one-to-one. There are infinitely many values of x such that \sin x=0, for example.

The standard function \sin^{-1}x has a domain of -1\le x\le1 and outputs values between -\dfrac\pi2 and \dfrac\pi2. This means that its inverse, \sin x, is indeed its inverse as long as -\dfrac\pi2\le x\le\dfrac\pi2.

\dfrac{3\pi}4 is larger than \dfrac\pi2 and thus does not fall in the "invertible part" of the domain of \sin x. We have

\sin\dfrac{3\pi}4=\dfrac1{\sqrt2}

which is a value between -1 and 1, so that

\sin^{-1}\left(\sin\dfrac{3\pi}4\right)=\sin^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

If we wanted to recover \dfrac{3\pi}4, we'd have to redefine \sin^{-1}x or define a new inverse function that works on a different branch of the domain of \sin x.

7 0
3 years ago
What is the product of 45 and 60?
Feliz [49]
<u><em>45×60=2700</em></u>
<u><em>And to check divide </em></u>
<u><em>2700÷60=40</em></u>
<u><em>2700÷40=60</em></u>
<u><em>Have a great time miss!</em></u>
7 0
3 years ago
Read 2 more answers
A.)List the 4 steps outlined in the lesson on solving equations. (1 points)
melomori [17]

For this case we must solve the following equations:

5x + 7 = 3x + 21

We subtract 3x on both sides of the equation:

5x-3x + 7 = 21

We subtract 7 on both sides of the equation:

5x-3x + 21-72x = 14

We divide between 2 on both sides of the equation:

x = \frac {14} {2}\\x = 7

The second equation is:

3x-2 (5-x) = - 3 (x-10) + 3x

We apply distributive property to the terms of parentheses:

3x-10 + 2x = -3x + 30 + 3x

We add common terms:

5x-10 = 30

We add 10 to both sides of the equation:

5x = 30 + 10\\5x = 40

We divide between 5 on both sides of the equation:

x = \frac {40} {5}\\x = 8

Third equation:

5 (x + 1) = 3 (2x + 3) +5

We apply distributive property to the terms within parentheses:

5x + 5 = 6x + 9 + 5

We add similar terms:

5x + 5 = 6x + 14

We subtract 6x on both sides of the equation:

5x-6x + 5 = 14

We subtract 5 on both sides of the equation:

-x = 14-5\\-x = 9\\x = -9

Answer:

x = 7\\x = 8\\x = -9

6 0
3 years ago
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