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rewona [7]
3 years ago
13

How does density and flammability explain how carbon dioxide could be coming from the bath bomb?

Chemistry
1 answer:
tresset_1 [31]3 years ago
3 0

The melting point is 152.7 C°, the boiling/decomposing point is 310 C°, and the density is 1.665 g/cm³. How are Bath bombs made? Baking soda is derived from soda ash.

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At high temperatures, carbon reacts with O2 to produce CO as follows: C(s) O2(g) 2CO(g). When 0.350 mol of O2 and excess carbon
777dan777 [17]

Answer:

Value of K_{c} is 0.090.

Explanation:

Initial molarity of O_{2} = \frac{0.350}{5.00}M = 0.0700 M

Construct an ICE table corresponding to the combustion reaction of carbon to determine K_{c}

                       C(s)+O_{2}(g)\rightarrow 2CO(g)

              I (M):    -      0.0700        0

             C (M):  -          -x             +2x

             E (M):   -    0.0700-x       2x

So, K_{c}=\frac{[CO]^{2}}{[O_{2}]}  , where [CO] and [O_{2}] represents equilibrium concentration of CO and O_{2} respectively.

Here, [CO]=2x=0.060

       ⇒x = 0.030

So, [O_{2}] = 0.0700-x = (0.0700-0.030) = 0.040

Hence,  K_{c}=\frac{(0.060)^{2}}{0.040}=0.090

4 0
3 years ago
Which of the following breaks and forms bonds?
svp [43]
Your answer would be "Chemical Change"
7 0
3 years ago
Uranium-235 has a half-life of 713 million years, while carbon-14 has a half-life of about 5,730 years. Which isotope would be m
nirvana33 [79]
Uranium-235 is more useful.
3 0
3 years ago
Read 2 more answers
A spoonful of salt is stirred into a pot of water.The salt is a
pshichka [43]

Answer:

the salt is a solute in this instance

4 0
3 years ago
Titration Volume & Concentration
polet [3.4K]

Answer:

18,1 mL of a 0,304M HCl solution.

Explanation:

The neutralization reaction of Ba(OH)₂ with HCl is:

2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O

The moles of 17,1 mL≡0,0171L of a 0,161M Ba(OH)₂ solution are:

0,0171L*\frac{0,161moles}{L} = 2,7531x10⁻³moles of Ba(OH)₂

By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:

2,7531x10^{-3}molBa(OH)_{2}*\frac{2molHCl}{1molBa(OH)_{2}} = 5,5062x10⁻³moles of HCl.

The volume of a 0,304M HCl solution for a complete neutralization is:

5,5062x10^{-3}molHCl*\frac{1L}{0,304mol} = 0,0181L≡18,1mL

I hope it helps!

4 0
3 years ago
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