Question

What mass of aluminum at 144 Celsius will increase the temperature of 100 g of water by from 10 C to 15 C?

Answer 1

Answer:

$m_{Al} = 18.019\,g$

Explanation:

There is a heating process between an aluminium piece and water, which is described by the First Law of Thermodynamics:

$Q_{Al} = - Q_{w}$

$m_{Al}\cdot c_{Al}\cdot (T_{o,Al}-T) = m_{w}\cdot c_{w}\cdot (T-T_{o,w})$

The mass of the aluminium piece is therefore cleared and known variables are substituted:

$m_{Al} = \frac{m_{w}\cdot c_{w}\cdot (T-T_{o,w})}{c_{Al}\cdot (T_{o,Al}-T)}$

$m_{Al} = \frac{(100\,g)\cdot \left(4.184\,\frac{J}{g\cdot^{\circ}C} \right)\cdot (15^{\circ}C-10^{\circ}C)}{\left(0.900\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (144^{\circ}C-15^{\circ}C)}$

$m_{Al} = 18.019\,g$