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Ostrovityanka [42]
3 years ago
12

NEED HELP PLEASE! BEEN ASKING FOR HELP SINCE 5:15PM (35 MINUTES)

Mathematics
1 answer:
QveST [7]3 years ago
8 0

Answer:

It makes sense that the solution is also what is listed because they added up how many bananas were purchased and how many grapes were purchased.  Then they totalled how much each person spent.

Step-by-step explanation:

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If there are 624 calories in 3 servings, how many calories are in 1 serving
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208 calories

Step-by-step explanation:

You have to divide 624 by 3, and you get 208.

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the seven houses on Kent lane are numbered from 1 to 7 .the local newspaper choose two of the houses at random to receive a free
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Is one side of a rectangular fish tank best represented by a point, line, plane, or ray?
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Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
4 years ago
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