Question

What is the area of rectangle ABCD with vertices A -3,0 B 3,2 C 4,-1 D -2,-3

Answer 1

For this, simply find the width and length by finding the distance between the two points. This can be done using the equation $\sqrt{(y2 - y1)^2 + (x2 - x1)^2}$

AB(length): $\sqrt{(0 - 2)^2 + (3 - (-3))^2}$

--> $\sqrt{-2^2 + 6^2}$

---> $\sqrt{40}$ = 6.32

BC(width): $\sqrt{(2 - (-1))^2 + (4 - 3)^2$

--> $\sqrt{(2 + 1)^2 + 1^2}$

---> $\sqrt{27 + 1}$

----> $\sqrt{28}$ = 5.29 ≈ 5.3

Area = 33.496 ≈ 33.5