1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brut [27]
4 years ago
12

A box sits on a horizontal wooden ramp. The coefficient of static friction between the box and the ramp is 0.34. You grab one en

d of the ramp and lift it up, keeping the other end of the ramp on the ground. What is the angle between the ramp and the horizontal direction when the box begins to slide down the ramp?

Physics
1 answer:
olya-2409 [2.1K]4 years ago
4 0

Answer:

The angle between the ramp and the horizontal direction is 18.7°.

Explanation:

Given that,

Coefficient of static friction = 0.34

According to figure,

The normal force is equal to the y component of weight of the box

N=W\cos\theta....(I)

We need to calculate the angle between the ramp and the horizontal direction

Using frictional force

f_{\mu}=\mu\ N

Put the value of frictional force and N into the formula

W\sin\theta=0.34\timesW\cos\theta

\tan\theta=0.34

\theta=\tan^{-1}(0.34)

\theta=18.7^{\circ}

Hence, The angle between the ramp and the horizontal direction is 18.7°.

You might be interested in
URGENT. Physics quiz on force, distance, etc. will reward brainliest.
goblinko [34]

13a) 9 J

The work done is equal to the area under the curve between x=0 cm and x=30 cm. However, first we should find the magnitude of the force for x=30 cm. If we notice that the force is proportional to the stretching x, we can set the following proportion to find the value of F for x=30 cm:

10 N : 5 cm = x : 30 cm

x=\frac{30 cm \cdot 10 N}{5 cm}=60 N

And so, the work done is

W=Area=\frac{1}{2}(base)(height)=\frac{1}{2}(0.30 m)(60 N)=9 J


13b) 24.5 m/s

The kinetic energy gained by the arrow is equal to the work done in stretching the bow:

K=W=9 J

Given the formula for the kinetic energy:

K=\frac{1}{2}mv^2

we can find the speed v of the arrow:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2\cdot 9J}{0.030 kg}}=24.5 m/s


13c) 30.6 m

If shot vertically upward, at the point of maximum height all the initial kinetic energy of the arrow is converted into gravitational potential energy:

\frac{1}{2}mv^2 = mgh

Re-arranging the formula and using the initial speed of the arrow, we can find its maximum height h:

h=\frac{v^2}{2g}=\frac{(24.5 m/s)^2}{2(9.81 m/s^2)}=30.6 m


14) 20 m/s

We can solve the problem by using the work-energy theorem. In fact, the work done by the frictional force of the brake is equal to the change in kinetic energy of the car:

W=\Delta K=K_f -K_i

Fd=\frac{1}{2}mv^2-\frac{1}{2}mu^2

where

F=-2500 N is the force applied by the brakes (with a negative sign, since it is opposite to the displacement of the car)

d=100 m is the displacement of the car

m=1000 kg is the car's mass

v is the final speed of the car

u=30 m/s is the initial speed of the car

By re-arranging the equation, we can find v:

v=\sqrt{\frac{2(Fd+\frac{1}{2}mu^2)}{m}}=20 m/s


15) 5.0 m/s

We can solve the problem by using the law of conservation of energy:

U_i + K_i = U_f + K_f\\mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where

m is the mass of the pendulum

h_i=1.2 m is the initial height of the pendulum

u=3 m/s is the initial speed of the pendulum

h_f=0.4 m is the final height of the pendulum

v is the final speed of the pendulum

Re-arranging the equation, we can find v:

v=\sqrt{2gh_i + u^2 - 2gh_f}=5.0 m/s


16) Point B (at the top of the loop)

Gravitational potential energy is defined as:

U=mgh

where m is the mass, g is the gravitational acceleration and h is the height above the ground. Therefore, we see that the potential energy is proportional to h: the higher the ball above the ground, the greater its potential energy. In this example, the point of maximum height is point B, therefore it is the point where the ball has the largest potential energy.


17) Law of conservation of energy: the total mechanical energy of an isolated object is conserved (if no frictional force act on it)

Example: A stone left falling from rest from a cliff. Let's call h the height of the cliff, m the mass of the stone. The mechanical energy of the stone is constant, and it is sum of the potential energy and kinetic energy:

E=U+K

At the top of the cliff, the kinetic energy is zero (the stone is at rest), so all its energy is potential energy:

E_i = U_i = mgh

When the stone falls, its energy is converted into kinetic energy. Just before hitting the ground, the height has become zero, h=0, so the potential energy is zero and all the mechanical energy is now kinetic energy:

E_f=K_f=\frac{1}{2}mv^2

since the mechanical energy must be conserved, we can write

E_i=E_f\\mgh = \frac{1}{2}mv^2\\2gh=v^2


6 0
4 years ago
When a car comes to a stop the car's brakes create an?
yawa3891 [41]
<span>Increased pressure to stop the movement. The brake reduces the acceleration of the engine. The brake absorbs energy at the wheels when it is applied to moving vehicles. It applies a counter torque to the engine. The friction force created by the break stops the vehicle.</span>
3 0
3 years ago
If Faraday had used a more powerful battery in his experiments with electromagnetic induction, what effect would this have had o
USPshnik [31]

Answer:

The value of current generated would increase.

Explanation:

Electromagnetic induction is the process by which an electromotive force is induced due to a variation of magnetic field.

The induced current is directly proportional to rate at which the coil cuts the magnetic field. Using more powerful battery in the experiment would increase the rate at the the coil cuts the magnetic field, therefore increasing the rate of variation in the magnetic field. This effect would cause a greater deflection on the galvanometer's scale, showing an increase in the current generated.

This experiment proves that an alternating current can be produced from magnetic field.

6 0
4 years ago
As an object moves from point A to point B only two forces act onit: one force is nonconservative and does -30 J of work, the ot
Romashka-Z-Leto [24]

To solve this problem we will apply the principles of energy conservation. On the one hand we have that the work done by the non-conservative force is equivalent to -30J while the work done by the conservative force is 50J.

This leads to the direct conclusion that the resulting energy is 20J.

The conservative force is linked to the movement caused by the sum of the two energies, therefore there is an increase in kinetic energy. The decrease in the mechanical energy of the system is directly due to the loss given by the non-conservative force, therefore there is a decrease in mechanical energy.

Therefore the correct answer is A. Kintetic energy increases and mechanical energy decreases.

7 0
3 years ago
A skateboarder travels on a horizontal surface with an initial velocity of 4.0 m/s toward the south and a constant acceleration
Alenkinab [10]

Answer:

a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s

Explanation:

a)

  • As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
  • This means that we can use the kinematic equations for displacements along both axes.
  • In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:

        x =\frac{1}{2}*a*t^{2} (1)

  • In the y-direction, as no acceleration is acting on the skateboarder, we can write  the following displacement equation:

        y = v_{0y} * t  (2)

  • For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:

       x =\frac{1}{2}*a*t^{2} =\frac{1}{2} * 1.8 m/s2*(0.6s)^{2}\\ x = 0.32 m

b)

  • From (2) we can get the position on the y-axis (displacement from the origin) as follows:

        y = v_{0y} * t  =  -4 m/s * 0.6 s = -2.4 m

c)

  • In the x- direction, we can find the component of the velocity along this direction, as follows:

        v_{fx} = a*t

  • Replacing by the values, we have:

        v_{fx} = a*t = 1.8 m/s2 * 0.6 s = 1.08 m/s

d)

  • As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we  have:

        vfy = voy = -4 m/s

8 0
4 years ago
Other questions:
  • PLZ ANSWER THESE 3 QUESTIONS!! When do you use a power equation? When do you use an energy equation? When do you use the efficie
    10·1 answer
  • A person doing chin-up weighs 700.0 N, disregarding the weight of the arms. During the first 25.0 cm of the lift, each arm exert
    8·2 answers
  • The refractive index of a certain glass is 1.66. For what incident angle is light reflected
    6·1 answer
  • What two things are necessary for work to be done on an object?
    5·1 answer
  • A loaded flatbottom barge floats in fresh wa-ter. The bottom of the barge is 4.09 m belowthe water line. When the barge is empty
    11·1 answer
  • What is the mass of a substance with a density of 9g/cm3 and a volume of 4cm3
    11·1 answer
  • Si el número masico del elemento litio es 7 ¿cual es su nucleo?
    13·1 answer
  • Design your own roller coaster
    15·1 answer
  • How does the sound of the recorder travel through the air?
    12·2 answers
  • Choose the statements that correctly describe a scientific theory. Select all that apply.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!