Answer:
Explanation:
Given that,
A system can detect objects as small as 19.1 cm i.e. 0.191 m. It is the wavelength.
We know that,
Frequency, 
So,
So, the frequency of such a system is equal to
.
Answer:
Explanation:
Given equation is ,
x =t + 2 t³ ,
dx/dt = velocity ( v ) = 1 + 6 t²
a) kinetic energy = 1/2 m v² = .5 x 4 ( 1 + 6 t² )² = 2 ( 1 + 6 t²)²
b ) Acceleration = dv /dt = 12 t .
force( F ) = mass x acceleration = 4 x 12 t = 48 t
Power = force x velocity = 48 t x ( 1 + 6 t²). = 48 t + 288 t³ )
work done = ∫ F dx =∫ 48 t x( 1 + 6t² )dt ; = [48t²/2 + 48 x 6 x t³ /3 = 24 t² + 96 t³ )]₀² = 864 J
882 divided by 9.81 (this is acceleration due to gravity) it equals 89.91
Answer:
1240 m/s
Explanation:
[Do you mean 0.035 kg bullet?]
Since the momentum of the system is conserved,
Let u m/s be the initial velocity of the bullet
0.035u = 8.6(5+0.035)
u ~= 1237.1714 m/s
u = 1240 m/s (3 sig. fig.)
