Question

A loaded flatbottom barge floats in fresh wa-ter. The bottom of the barge is 4.09 m belowthe water line. When the barge is empty thebarge’s bottom is only 1.8 m below the waterline.What is the difference between the pressureon the bottom of the loaded barge and thepressure at the water line?Answer in units of Pa.006 (part 2 of 2) 10.0 pointsIf the surface area of the bottom of the barge

Answer 1

Answer:

The value is $\Delta P = 40082 \ Pa$

Explanation:

From the question we are told that

   The length of the bottom of the barge  below the water line when loaded  is $d_2 = 4.09 \ m$

      The length of the bottom of the barge  below the water line when empty   is $d_1 = 1.80 \ m$

Generally the difference in pressure is mathematically represented as

           $\Delta P = \rho * g * d_2$

Here $\rho$ is the density of water with value $\rho = 1000 \ kg/m^3$

           $\Delta P = 1000 * 9.8 * ( 4.09 )$

=>        $\Delta P = 40082 \ Pa$