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tekilochka [14]
3 years ago
11

A loaded flatbottom barge floats in fresh wa-ter. The bottom of the barge is 4.09 m belowthe water line. When the barge is empty

thebarge’s bottom is only 1.8 m below the waterline.What is the difference between the pressureon the bottom of the loaded barge and thepressure at the water line?Answer in units of Pa.006 (part 2 of 2) 10.0 pointsIf the surface area of the bottom of the barge
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

The value is \Delta  P  =  40082 \  Pa

Explanation:

From the question we are told that

   The length of the bottom of the barge  below the water line when loaded  is d_2 =  4.09 \ m

      The length of the bottom of the barge  below the water line when empty   is d_1  =  1.80  \ m

Generally the difference in pressure is mathematically represented as

           \Delta  P  =  \rho *  g  * d_2

Here \rho is the density of water with value \rho =  1000 \  kg/m^3

           \Delta  P  =  1000 *  9.8   *  ( 4.09 )

=>        \Delta  P  =  40082 \  Pa

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