1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klasskru [66]
3 years ago
8

Draw the Electronic configuration for sulphur chloride

Chemistry
2 answers:
Alex17521 [72]3 years ago
3 0

Answer:

In writing the electron configuration for Sulfur the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for sulfur go in the 2s orbital. Therefore the sulfur electron configuration will be 1s22s22p63s23p4.

Stells [14]3 years ago
3 0

Answer:

The sulfur electron configuration will be 1s22s22p63s23p4.

You might be interested in
What mass of solute is needed to prepare each of the following solutions?
noname [10]

Answer:

a. 21.7824 g

b. 0.2362 g

c. 31.5273 g

Please see the answers in the picture attached below.

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

5 0
4 years ago
Answer right = Brainliest!!
amid [387]
A b and e is are the answers
8 0
3 years ago
On the periodic table, the average atomic mass for carbon is 12.01 g. Why is it not exactly 12.00?
KiRa [710]
The average the natural abundances of the various isotopes of carbon to arrive at the fractional mass.

5 0
3 years ago
For the reaction: 3 H2(g) + N2(g) <--> 2 NH3(g), the concentrations at equilbrium were [H2] = 0.10 M, [N2] = 0.10 M, and [
masya89 [10]

The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵

<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>

It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.

Hence, the equilibrium constant of the reaction in discuss is;

K = [5.6]²/[0.10]³[0.10]

k = 5.6² × 10⁴

k = 3.136 × 10⁵

K = 3.1 × 10⁵.

Read more on equilibrium constant;

brainly.com/question/1619133

#SPJ1

5 0
2 years ago
The common pathway for the oxidation of glucose and fatty acids is ________.
finlep [7]
The citric acid cycle should be the answer.
3 0
3 years ago
Other questions:
  • One type of breathalyzer employs a fuel cell to measure the quantity of alcohol in the breath. When a suspect blows into the bre
    12·1 answer
  • Which igneous rock is an extrusive rock?​
    13·1 answer
  • What is the mass in grams of 1.22 x 10 to the 24th power atoms of gallium?
    6·2 answers
  • Which statement best describes the energy of activation?
    5·2 answers
  • Do biotic factors contain cells
    6·1 answer
  • Please help me fast What is the Molarity of 100g of Vit. C (C6HBO6) with 2.5L of water?
    7·1 answer
  • Determine the pH of a solution of 1.45 M HCl solution
    14·2 answers
  • Which transformation represents light energy transforming into chemical energy?
    15·1 answer
  • 29. What is E for a system which has the following two steps:
    12·1 answer
  • Explain
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!